web analytics

Slide26.JPG

Slide27.JPG

View
  1. Chapter 11 Class 9 Constructions
  2. Serial order wise
Ask Download

Transcript

Construct a triangle ABC, in which ∠B = 60°, ∠C = 45° and AB + BC + CA = 11 cm Steps of Construction: 1.Draw a line segment PQ equal to AB  + BC + CA = 11 cm. Make ∠ LPQ = ∠B = 60° and ∠ MQP= ∠C = 45° Bisect ∠ LPQ and ∠ MQP. Let these bisectors intersect at a point A . Draw perpendicular bisectors of line AP and AQ Let XY intersect PQ at B and RS intersect PQ at C. Join AB and AC Thus, Δ ABC is a the required triangle

About the Author

Davneet Singh's photo - Teacher, Computer Engineer, Marketer
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He provides courses for Mathematics from Class 9 to 12. You can ask questions here.
Jail