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  1. Chapter 11 Class 9 Constructions
  2. Serial order wise
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Construct a triangle ABC, in which ∠B = 60°, ∠C = 45° and AB + BC + CA = 11 cm Steps of Construction: 1.Draw a line segment PQ equal to AB  + BC + CA = 11 cm. Make ∠ LPQ = ∠B = 60° and ∠ MQP= ∠C = 45° Bisect ∠ LPQ and ∠ MQP. Let these bisectors intersect at a point A . Draw perpendicular bisectors of line AP and AQ Let XY intersect PQ at B and RS intersect PQ at C. Join AB and AC Thus, Δ ABC is a the required triangle

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He provides courses for Mathematics from Class 9 to 12. You can ask questions here.