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Ex 11.1

Ex 11.1, 1
Deleted for CBSE Board 2023 Exams

Ex 11.1, 2 Important Deleted for CBSE Board 2023 Exams

Ex 11.1, 3 (i) Deleted for CBSE Board 2023 Exams

Ex 11.1, 3 (ii) Important Deleted for CBSE Board 2023 Exams

Ex 11.1, 3 (iii) Important Deleted for CBSE Board 2023 Exams

Ex 11.1, 4 (i) Important Deleted for CBSE Board 2023 Exams You are here

Ex 11.1, 4 (ii) Important Deleted for CBSE Board 2023 Exams

Ex 11.1, 4 (iii) Deleted for CBSE Board 2023 Exams

Ex 11.1, 5 Deleted for CBSE Board 2023 Exams

Construct an angle of 120° using compass Deleted for CBSE Board 2023 Exams

Last updated at Aug. 13, 2021 by Teachoo

Maths Crash Course - Live lectures + all videos + Real time Doubt solving!

Ex 11.1, 4 Construct the following angles and verify by measuring them by a Protractor : 75° 75° = 60° + 15° 75° = 60° + (𝟑𝟎°)/𝟐 So, to we make 75° , we make 60° and then bisector of 30° Steps of construction Draw a ray OA. Taking O as center and any radius, draw an arc cutting OA at B. 3. Now, with B as center and same radius as before, draw an arc intersecting the previously drawn arc at point C. 4. Now, with C as center, and same radius, draw another arc intersecting the previously drawn arc at point D 5. Draw ray OE passing through C and ray OF passing through D Thus, ∠ AOE = 60° and ∠ EOF = 60° 6. Taking C and D as center , with radius more than 1/2CD, draw arcs intersecting at P. 7. Join OP Thus, ∠ AOE = 60° and ∠ EOF = 60° 6. Taking C and D as center , with radius more than 1/2CD, draw arcs intersecting at P. 7. Join OP Thus, ∠ EOP = 30° Now, we bisect ∠ EOP i.e. (30°)/2 = 15° 7. Mark point Q where OP intersects the arc 8. Taking Q and C as center , with radius more than 1/2QC, draw arcs intersecting at R. 9. Join OR Thus, ∠ AOR = 75° On measuring the ∠ AOR by protractor, we find that ∠ AOR = 75° Thus, the construction is verified