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Ex 11.1

Ex 11.1, 1
Deleted for CBSE Board 2023 Exams

Ex 11.1, 2 Important Deleted for CBSE Board 2023 Exams

Ex 11.1, 3 (i) Deleted for CBSE Board 2023 Exams

Ex 11.1, 3 (ii) Important Deleted for CBSE Board 2023 Exams

Ex 11.1, 3 (iii) Important Deleted for CBSE Board 2023 Exams

Ex 11.1, 4 (i) Important Deleted for CBSE Board 2023 Exams

Ex 11.1, 4 (ii) Important Deleted for CBSE Board 2023 Exams

Ex 11.1, 4 (iii) Deleted for CBSE Board 2023 Exams You are here

Ex 11.1, 5 Deleted for CBSE Board 2023 Exams

Construct an angle of 120° using compass Deleted for CBSE Board 2023 Exams

Last updated at Aug. 13, 2021 by Teachoo

Ex 11.1, 4 Construct the following angles and verify by measuring them by a Protractor : 135° 135° = 90° + 45° So, to make 135° , we make 90° and then 45° Steps of construction Draw a line OAA’. Taking O as center and any radius, draw an arc cutting OA at B. 3. Now, with B as center and same radius as before, draw an arc intersecting the previously drawn arc at point C. 4. With C as center and the same radius, draw an arc cutting the arc at D. 5. With C and D as centers and radius more than 1/2 CD, draw two arcs intersecting at P. Thus, ∠ AOP = 90° Also, ∠ A’OP = 90° So, we bisect ∠ A’OP Mark point Q where OP intersects the arc With B’ and Q as centers and radius more than 1/2 B’Q, draw two arcs intersecting at R. Join OR. ∴ ∠ POR = 45° Thus, ∠ AOR = ∠ AOP + ∠ POR = 90° + 35° = 135° ∴ ∠ AOR = 135°