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Ex 11.1, 3 (ii) - Ex 11.1

Ex 11.1, 3 (ii) - Chapter 11 Class 9 Constructions - Part 2
Ex 11.1, 3 (ii) - Chapter 11 Class 9 Constructions - Part 3
Ex 11.1, 3 (ii) - Chapter 11 Class 9 Constructions - Part 4
Ex 11.1, 3 (ii) - Chapter 11 Class 9 Constructions - Part 5

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Ex 11.1, 3 Construct the angles of the following measurements : 221/2° 221/2 = 45/2 So, we make 45° and then make its bisector Steps of construction Draw a ray OA. Taking O as center and any radius, draw an arc cutting OA at B. 3. Now, taking B as center and with the same radius as before, draw an arc intersecting the previously drawn arc at point C. 4. With C as center and the same radius, draw an arc cutting the arc at D 5. With C and D as centers and radius more than 1/2 CD, draw two arcs intersecting at P. 6. Join OP. Thus, ∠ AOP = 90° Now we draw bisector of ∠ AOP 7. Let OP intersect the original arc at point Q 8. Now, taking B and Q as centers, and radius greater than 1/2 BQ, draw two arcs intersecting at R. 9. Join OR. Thus, ∠ AOR = 45° Now we draw bisector of ∠ AOR 10. Mark point S where ray OR intersects the arc 11. Now, taking B and S as centers, and radius greater than 1/2 BS, draw two arcs intersecting at T. 12. Join OT. Thus, ∠ AOT = 22𝟏/𝟐°

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.