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Ex 13.1, 4 - Chapter 13 Class 11 Statistics
Last updated at May 29, 2023 by Teachoo
Chapter 13 Class 11 Statistics
Serial order wise
Transcript
Ex15.1, 4 Find the mean deviation about the median for the data 36, 72, 46, 42, 60, 45, 53, 46, 51, 49 Arranging data in ascending order, 36, 42, 45, 46, 46, 49, 51, 53, 60, 72 Here, n = number of observations = 10 (even) Since n is even Median = (( /2)^ + ( /2 + 1)^ )/2 M = ((10/2)^ + (10/2 + 1)^ )/2 M = (5^ + 6^ )/2 M = (46 + 49)/2 = 95/2 = 47.5 Thus, for 36, 42, 45, 46, 46, 49, 51, 53, 60, 72 Median = 47.5 Mean deviation about median = ( 128 | M| )/10 M.D.(M) = (( (|36 47.5| + |42 47.5| + |45 47.5| + |46 47.5| + |46 47.5| @+ |49 47.5| + |51 47.5| + |53 47.5|+ |60 47.5| + |72 47.5| )))/10 = (( (| 11.5| + | 5.5| + | 2.5| + | 1.5| + | 1.5| @+ |1.5| + |3.5|+ |5.5| + |12.5| + |24.5| )))/10 = (11.5 + 5.5 +2.5 + 1.5 + 1.5 + 1.5 + 3.5 + 5.5 + 12.5 + 24.5)/10 = 70/10 = 7
