web analytics

Ex 15.1, 3 - Find mean deviation about median - Class 11 - Mean deviation about median - Ungrouped

Slide4.PNG

  1. Chapter 15 Class 11 Statistics
  2. Serial order wise
Ask Download

Transcript

Ex 15.1, 3 Find the mean deviation about the median for the data. 13, 17, 16, 14, 11, 13, 10, 16, 11, 18, 12, 17 Arranging data in ascending order, 10, 11, 11, 12, 13, 13, 14, 16, 16, 17, 17, 18 Here, n = number of observations = 12 (even) Since n is even Median = 𝑛īˇŽ2īˇ¯īˇ¯īˇŽđ‘Ąâ„Žīˇ¯đ‘œđ‘đ‘ đ‘’đ‘Ÿđ‘Ŗ𝑎𝑡𝑖𝑜𝑛 + 𝑛īˇŽ2īˇ¯ + 1īˇ¯īˇŽđ‘Ąâ„Žīˇ¯đ‘œđ‘đ‘ đ‘’đ‘Ÿđ‘Ŗ𝑎𝑡𝑖𝑜𝑛īˇŽ2īˇ¯ M = 12īˇŽ2īˇ¯īˇ¯īˇŽđ‘Ąâ„Žīˇ¯đ‘œđ‘đ‘ đ‘’đ‘Ÿđ‘Ŗ𝑎𝑡𝑖𝑜𝑛 + 12īˇŽ2īˇ¯ + 1īˇ¯īˇŽđ‘Ąâ„Žīˇ¯đ‘œđ‘đ‘ đ‘’đ‘Ÿđ‘Ŗ𝑎𝑡𝑖𝑜𝑛īˇŽ2īˇ¯ M = 6īˇŽđ‘Ąâ„Žīˇ¯đ‘œđ‘đ‘ đ‘’đ‘Ÿđ‘Ŗ𝑎𝑡𝑖𝑜𝑛 + 7īˇŽđ‘Ąâ„Žīˇ¯đ‘œđ‘đ‘ đ‘’đ‘Ÿđ‘Ŗ𝑎𝑡𝑖𝑜𝑛īˇŽ2īˇ¯ M = 13 + 14īˇŽ2īˇ¯ = 27īˇŽ2īˇ¯ = 13.5 Thus, for 10, 11, 11, 12, 13, 13, 14, 16, 16, 17, 17, 18 Median = 13.5 Mean deviation about median = īˇŽīˇŽ đ‘Ĩ𝑖 −Mīˇ¯īˇ¯īˇŽ12īˇ¯ = 10 − 13.5īˇ¯ + 11 − 13.5īˇ¯ + 11 − 13.5īˇ¯ + 12 − 13.5īˇ¯ + 13 − 13.5īˇ¯+ 13 − 13.5īˇ¯īˇŽ+ 14 − 13.5īˇ¯ + 16 − 13.5īˇ¯ + 16 − 13.5īˇ¯ + 17 − 13.5īˇ¯ + 17 − 13.5īˇ¯+ 18 − 13.5īˇ¯īˇ¯īˇ¯īˇŽ12īˇ¯ = −3.5īˇ¯ + −2.5īˇ¯ + −2.5īˇ¯ + −1.5īˇ¯ + −0.5īˇ¯ + −0.5īˇ¯īˇŽ+ 0.5īˇ¯ + 2.5īˇ¯ + 2.5īˇ¯+ 3.5īˇ¯ + 3.5īˇ¯ + 4.5īˇ¯ īˇ¯īˇ¯īˇŽ12īˇ¯ = 3.5 + 2.5 + 2.5 + 1.5 + 0.5 + 0.5 + 0.5 + 2.5 + 2.5 + 3.5 + 3.5 + 4.5īˇŽ12īˇ¯ = 28īˇŽ12īˇ¯ = 2.33

About the Author

CA Maninder Singh's photo - Expert in Practical Accounts, Taxation and Efiling
CA Maninder Singh
CA Maninder Singh is a Chartered Accountant for the past 8 years. He provides courses for Practical Accounts, Taxation and Efiling at teachoo.com .
Jail