Ex 13.1

Chapter 13 Class 11 Statistics
Serial order wise

### Transcript

Ex 13.1, 3 Find the mean deviation about the median for the data. 13, 17, 16, 14, 11, 13, 10, 16, 11, 18, 12, 17 Arranging data in ascending order, 10, 11, 11, 12, 13, 13, 14, 16, 16, 17, 17, 18 Here, n = number of observations = 12 (even) Since n is even Median = đīˇŽ2īˇ¯īˇ¯īˇŽđĄâīˇ¯đđđ đđđŖđđĄđđđ + đīˇŽ2īˇ¯ + 1īˇ¯īˇŽđĄâīˇ¯đđđ đđđŖđđĄđđđīˇŽ2īˇ¯ M = 12īˇŽ2īˇ¯īˇ¯īˇŽđĄâīˇ¯đđđ đđđŖđđĄđđđ + 12īˇŽ2īˇ¯ + 1īˇ¯īˇŽđĄâīˇ¯đđđ đđđŖđđĄđđđīˇŽ2īˇ¯ M = 6īˇŽđĄâīˇ¯đđđ đđđŖđđĄđđđ + 7īˇŽđĄâīˇ¯đđđ đđđŖđđĄđđđīˇŽ2īˇ¯ M = 13 + 14īˇŽ2īˇ¯ = 27īˇŽ2īˇ¯ = 13.5 Thus, for 10, 11, 11, 12, 13, 13, 14, 16, 16, 17, 17, 18 Median = 13.5 Mean deviation about median = īˇŽīˇŽ đĨđ âMīˇ¯īˇ¯īˇŽ12īˇ¯ = 10 â 13.5īˇ¯ + 11 â 13.5īˇ¯ + 11 â 13.5īˇ¯ + 12 â 13.5īˇ¯ + 13 â 13.5īˇ¯+ 13 â 13.5īˇ¯īˇŽ+ 14 â 13.5īˇ¯ + 16 â 13.5īˇ¯ + 16 â 13.5īˇ¯ + 17 â 13.5īˇ¯ + 17 â 13.5īˇ¯+ 18 â 13.5īˇ¯īˇ¯īˇ¯īˇŽ12īˇ¯ = â3.5īˇ¯ + â2.5īˇ¯ + â2.5īˇ¯ + â1.5īˇ¯ + â0.5īˇ¯ + â0.5īˇ¯īˇŽ+ 0.5īˇ¯ + 2.5īˇ¯ + 2.5īˇ¯+ 3.5īˇ¯ + 3.5īˇ¯ + 4.5īˇ¯ īˇ¯īˇ¯īˇŽ12īˇ¯ = 3.5 + 2.5 + 2.5 + 1.5 + 0.5 + 0.5 + 0.5 + 2.5 + 2.5 + 3.5 + 3.5 + 4.5īˇŽ12īˇ¯ = 28īˇŽ12īˇ¯ = 2.33