Ex 15.1, 3 - Find mean deviation about median - Class 11 - Mean deviation about median - Ungrouped

Ex 15.1, 3 - Chapter 15 Class 11 Statistics - Part 2


Transcript

Ex 13.1, 3 Find the mean deviation about the median for the data. 13, 17, 16, 14, 11, 13, 10, 16, 11, 18, 12, 17 Arranging data in ascending order, 10, 11, 11, 12, 13, 13, 14, 16, 16, 17, 17, 18 Here, n = number of observations = 12 (even) Since n is even Median = ๐‘›๏ทฎ2๏ทฏ๏ทฏ๏ทฎ๐‘กโ„Ž๏ทฏ๐‘œ๐‘๐‘ ๐‘’๐‘Ÿ๐‘ฃ๐‘Ž๐‘ก๐‘–๐‘œ๐‘› + ๐‘›๏ทฎ2๏ทฏ + 1๏ทฏ๏ทฎ๐‘กโ„Ž๏ทฏ๐‘œ๐‘๐‘ ๐‘’๐‘Ÿ๐‘ฃ๐‘Ž๐‘ก๐‘–๐‘œ๐‘›๏ทฎ2๏ทฏ M = 12๏ทฎ2๏ทฏ๏ทฏ๏ทฎ๐‘กโ„Ž๏ทฏ๐‘œ๐‘๐‘ ๐‘’๐‘Ÿ๐‘ฃ๐‘Ž๐‘ก๐‘–๐‘œ๐‘› + 12๏ทฎ2๏ทฏ + 1๏ทฏ๏ทฎ๐‘กโ„Ž๏ทฏ๐‘œ๐‘๐‘ ๐‘’๐‘Ÿ๐‘ฃ๐‘Ž๐‘ก๐‘–๐‘œ๐‘›๏ทฎ2๏ทฏ M = 6๏ทฎ๐‘กโ„Ž๏ทฏ๐‘œ๐‘๐‘ ๐‘’๐‘Ÿ๐‘ฃ๐‘Ž๐‘ก๐‘–๐‘œ๐‘› + 7๏ทฎ๐‘กโ„Ž๏ทฏ๐‘œ๐‘๐‘ ๐‘’๐‘Ÿ๐‘ฃ๐‘Ž๐‘ก๐‘–๐‘œ๐‘›๏ทฎ2๏ทฏ M = 13 + 14๏ทฎ2๏ทฏ = 27๏ทฎ2๏ทฏ = 13.5 Thus, for 10, 11, 11, 12, 13, 13, 14, 16, 16, 17, 17, 18 Median = 13.5 Mean deviation about median = ๏ทฎ๏ทฎ ๐‘ฅ๐‘– โˆ’M๏ทฏ๏ทฏ๏ทฎ12๏ทฏ = 10 โˆ’ 13.5๏ทฏ + 11 โˆ’ 13.5๏ทฏ + 11 โˆ’ 13.5๏ทฏ + 12 โˆ’ 13.5๏ทฏ + 13 โˆ’ 13.5๏ทฏ+ 13 โˆ’ 13.5๏ทฏ๏ทฎ+ 14 โˆ’ 13.5๏ทฏ + 16 โˆ’ 13.5๏ทฏ + 16 โˆ’ 13.5๏ทฏ + 17 โˆ’ 13.5๏ทฏ + 17 โˆ’ 13.5๏ทฏ+ 18 โˆ’ 13.5๏ทฏ๏ทฏ๏ทฏ๏ทฎ12๏ทฏ = โˆ’3.5๏ทฏ + โˆ’2.5๏ทฏ + โˆ’2.5๏ทฏ + โˆ’1.5๏ทฏ + โˆ’0.5๏ทฏ + โˆ’0.5๏ทฏ๏ทฎ+ 0.5๏ทฏ + 2.5๏ทฏ + 2.5๏ทฏ+ 3.5๏ทฏ + 3.5๏ทฏ + 4.5๏ทฏ ๏ทฏ๏ทฏ๏ทฎ12๏ทฏ = 3.5 + 2.5 + 2.5 + 1.5 + 0.5 + 0.5 + 0.5 + 2.5 + 2.5 + 3.5 + 3.5 + 4.5๏ทฎ12๏ทฏ = 28๏ทฎ12๏ทฏ = 2.33

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