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  1. Chapter 15 Class 11 Statistics
  2. Serial order wise
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Ex 15.1, 2 Find the mean deviation about the mean for the data 38, 70, 48, 40, 42, 55, 63, 46, 54, 44 Mean of the given data = (๐‘†๐‘ข๐‘š ๐‘œ๐‘“ ๐‘Ž๐‘™๐‘™ ๐‘ก๐‘’๐‘Ÿ๐‘š๐‘ )/(๐‘‡๐‘œ๐‘ก๐‘Ž๐‘™ ๐‘›๐‘ข๐‘š๐‘๐‘’๐‘Ÿ ๐‘œ๐‘“ ๐‘ก๐‘’๐‘Ÿ๐‘š๐‘ ) ๐‘ฅ ฬ… = (38 + 70 + 48 + 40 + 42 + 55 + 63 + 46 + 54 + 44)/(10 ) = 500/10 = 50 38 38 โ€“ 50 = โ€“12 70 70 โ€“ 50 = 20 48 48 โ€“ 50 = โ€“2 40 40 โ€“ 50 = โ€“10 42 42 โ€“ 50 = โ€“8 55 63 46 54 44 Mean deviation about mean = ( โˆ‘128โ–’|๐‘ฅ๐‘– โˆ’ ๐‘ฅ ฬ… | )/10 = 84/10 = 8.4

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