Ex 15.2, 1 - Find mean and variance for 6, 7, 10, 12, 13 - Standard deviation and variance - Ungrouped data

  1. Chapter 15 Class 11 Statistics
  2. Serial order wise
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Ex 15.2, 1 - Chapter 15 Class 11 Statistics - NCERT Find the mean and variance for the data 6 , 7, 10, 12, 13, 4, 8, 12 xi x_i-x ฬ… (x_i-x ฬ… )^2 6 7 10 12 13 4 8 12 6 โ€“ 9 = โ€“3 7 โ€“ 9 = โ€“2 10 โ€“ 9 = 1 12 โ€“ 9 = 3 13 โ€“ 9 = 4 4 โ€“ 9 = โ€“5 8 โ€“ 9 = โ€“1 12 โ€“ 9 = 3 9 4 1 9 16 25 1 9 โˆ‘โ–’(๐‘ฅ_๐‘–โˆ’๐‘ฅ ฬ… )^2 = 74 Mean = (๐‘†๐‘ข๐‘š ๐‘œ๐‘“ ๐‘œ๐‘๐‘ ๐‘’๐‘Ÿ๐‘ฃ๐‘Ž๐‘ก๐‘–๐‘œ๐‘›๐‘ )/(๐‘๐‘ข๐‘š๐‘๐‘’๐‘Ÿ ๐‘œ๐‘“ ๐‘œ๐‘๐‘ ๐‘’๐‘Ÿ๐‘ฃ๐‘Ž๐‘ก๐‘–๐‘œ๐‘›๐‘ ) = (6 + 7 + 10 + 12 + 13 + 4 + 8 + 12)/8 = 72/8 = 9 Variance = (โˆ‘โ–’(๐‘ฅ_๐‘– โˆ’ ๐‘ฅ ฬ… )^2 )/๐‘› = 74/8 =๐Ÿ—.๐Ÿ๐Ÿ“

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