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Ex 15.2, 10 - Diameter of circles (in mm) drawn in a design - Standard deviation and variance - Continuous frequency (grouped data)

Ex 15.2,  10 - Chapter 15 Class 11 Statistics - Part 2
Ex 15.2,  10 - Chapter 15 Class 11 Statistics - Part 3


Transcript

Ex 15.2, 10 The diameters of circles (in mm) drawn in a design are given below: h = class size = 36.5 βˆ’ 32.5 = 4 Mean(π‘₯ Μ…) = A + (βˆ‘β–’π‘“π‘–π‘¦π‘–)/(βˆ‘β–’π‘“π‘–) Γ—β„Ž = 42.5 + 25/100 Γ—4 = 42.5 + 1/4 Γ—4 = 43.5 Variance (𝜎)2 = β„Ž2/N2 [π‘βˆ‘β–’π‘“π‘–π‘¦π‘–2 βˆ’ (βˆ‘β–’π‘“π‘–π‘¦π‘–)^2 ] = 42/1002 [100 Γ— (199) – (25)2] = 16/10000 [19900 βˆ’625] = 16/10000 Γ— 19275 = 30.84 ∴ Standard deviation (𝜎) = √Variance 𝜎 = √30.84 = 5.55

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.