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Ex 15.2, 6 - Chapter 15 Class 11 Statistics (Term 1)

Last updated at May 29, 2018 by

Ex 15.2, 6 - Find mean, standard deviation using short-cut - Standard deviation and variance - Discrete frequency (grouped data)

Ex 15.2, 6 - Chapter 15 Class 11 Statistics - Part 2

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Ex 15.2, 6 Find the mean and standard deviation using short-cut method. Mean = a + (∑▒𝑓𝑖𝑦𝑖)/(∑▒𝑓𝑖) × h = 64 + 0/100 ×1 = 64 Standard Deviation = ℎ/𝑁 √(𝑁∑▒𝑓𝑖𝑦𝑖2 − (∑▒𝑓𝑖𝑦𝑖)^2 ) "= " 1/100 √("100" ×"286 – " 〖(0)〗^2 ) = 1/100 √28600 = 169.1/100 = 1.691

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