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Ex 15.2, 6 - Find mean, standard deviation using short-cut - Standard deviation and variance - Discrete frequency (grouped data)

Ex 15.2,  6 - Chapter 15 Class 11 Statistics - Part 2

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Transcript

Ex 13.2, 6 Find the mean and standard deviation using short-cut method. Mean = a + (βˆ‘β–’π‘“π‘–π‘¦π‘–)/(βˆ‘β–’π‘“π‘–) Γ— h = 64 + 0/100 Γ—1 = 64 Standard Deviation = β„Ž/𝑁 √(π‘βˆ‘β–’π‘“π‘–π‘¦π‘–2 βˆ’ (βˆ‘β–’π‘“π‘–π‘¦π‘–)^2 ) "= " 1/100 √("100" Γ—"286 – " γ€–(0)γ€—^2 ) = 1/100 √28600 = 169.1/100 = 1.691

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