1. Chapter 15 Class 11 Statistics (Term 1)
  2. Serial order wise
  3. Ex 15.2

Ex 15.2, 6 - Chapter 15 Class 11 Statistics (Term 1)

Last updated at May 29, 2018 by

Ex 15.2, 6 - Find mean, standard deviation using short-cut - Standard deviation and variance - Discrete frequency (grouped data)

Ex 15.2, 6 - Chapter 15 Class 11 Statistics - Part 2

  1. Chapter 15 Class 11 Statistics (Term 1)
  2. Serial order wise

    3. Ex 15.2

    Ex 15.3ย โ†’

Transcript

Ex 15.2, 6 Find the mean and standard deviation using short-cut method. Mean = a + (โˆ‘โ–’๐‘“๐‘–๐‘ฆ๐‘–)/(โˆ‘โ–’๐‘“๐‘–) ร— h = 64 + 0/100 ร—1 = 64 Standard Deviation = โ„Ž/๐‘ โˆš(๐‘โˆ‘โ–’๐‘“๐‘–๐‘ฆ๐‘–2 โˆ’ (โˆ‘โ–’๐‘“๐‘–๐‘ฆ๐‘–)^2 ) "= " 1/100 โˆš("100" ร—"286 โ€“ " ใ€–(0)ใ€—^2 ) = 1/100 โˆš28600 = 169.1/100 = 1.691

Chapter 15 Class 11 Statistics (Term 1)
Serial order wise

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