Ex 15.2, 9 - Find mean, variance, standard deviation using short - Standard deviation and variance - Continuous frequency (grouped data)

Ex 15.2,  9 - Chapter 15 Class 11 Statistics - Part 2
Ex 15.2,  9 - Chapter 15 Class 11 Statistics - Part 3

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Transcript

Ex15.2, 9 Find the mean, variance and standard deviation using short-cut method Mean(𝑥 ̅) = A + (∑▒𝑓𝑖𝑦𝑖)/(∑▒𝑓𝑖) ×ℎ where A = assumed mean = 92.5 𝑦_𝑖=(𝑥_𝑖 − 𝐴)/ℎ h = class size = 75 − 70 = 5 Variance (𝜎)2 = ℎ2/N2 [𝑁∑▒𝑓𝑖𝑦𝑖2 − (∑▒𝑓𝑖𝑦𝑖)^2 ] = 52/602 [N × (254) – (6)2] = 25/3600 [60 ×254 −36] = 25/3600 × 15204 = 105.58 ∴ Standard deviation (𝜎) = √Variance = √105.58 = 10.27

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