Ex 13.1, 3 - Find mean deviation about median - Class 11 - Ex 13.1

part 2 - Ex 13.1, 3 - Ex 13.1 - Serial order wise - Chapter 13 Class 11 Statistics

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Ex 13.1, 3 Find the mean deviation about the median for the data. 13, 17, 16, 14, 11, 13, 10, 16, 11, 18, 12, 17 Arranging data in ascending order, 10, 11, 11, 12, 13, 13, 14, 16, 16, 17, 17, 18 Here, n = number of observations = 12 (even) Since n is even Median = š‘›ļ·®2ļ·Æļ·Æļ·®š‘”ā„Žļ·Æš‘œš‘š‘ š‘’š‘Ÿš‘£š‘Žš‘”š‘–š‘œš‘› + š‘›ļ·®2ļ·Æ + 1ļ·Æļ·®š‘”ā„Žļ·Æš‘œš‘š‘ š‘’š‘Ÿš‘£š‘Žš‘”š‘–š‘œš‘›ļ·®2ļ·Æ M = 12ļ·®2ļ·Æļ·Æļ·®š‘”ā„Žļ·Æš‘œš‘š‘ š‘’š‘Ÿš‘£š‘Žš‘”š‘–š‘œš‘› + 12ļ·®2ļ·Æ + 1ļ·Æļ·®š‘”ā„Žļ·Æš‘œš‘š‘ š‘’š‘Ÿš‘£š‘Žš‘”š‘–š‘œš‘›ļ·®2ļ·Æ M = 6ļ·®š‘”ā„Žļ·Æš‘œš‘š‘ š‘’š‘Ÿš‘£š‘Žš‘”š‘–š‘œš‘› + 7ļ·®š‘”ā„Žļ·Æš‘œš‘š‘ š‘’š‘Ÿš‘£š‘Žš‘”š‘–š‘œš‘›ļ·®2ļ·Æ M = 13 + 14ļ·®2ļ·Æ = 27ļ·®2ļ·Æ = 13.5 Thus, for 10, 11, 11, 12, 13, 13, 14, 16, 16, 17, 17, 18 Median = 13.5 Mean deviation about median = ﷮﷮ š‘„š‘– āˆ’Mļ·Æļ·Æļ·®12ļ·Æ = 10 āˆ’ 13.5ļ·Æ + 11 āˆ’ 13.5ļ·Æ + 11 āˆ’ 13.5ļ·Æ + 12 āˆ’ 13.5ļ·Æ + 13 āˆ’ 13.5ļ·Æ+ 13 āˆ’ 13.5ļ·Æļ·®+ 14 āˆ’ 13.5ļ·Æ + 16 āˆ’ 13.5ļ·Æ + 16 āˆ’ 13.5ļ·Æ + 17 āˆ’ 13.5ļ·Æ + 17 āˆ’ 13.5ļ·Æ+ 18 āˆ’ 13.5ļ·Æļ·Æļ·Æļ·®12ļ·Æ = āˆ’3.5ļ·Æ + āˆ’2.5ļ·Æ + āˆ’2.5ļ·Æ + āˆ’1.5ļ·Æ + āˆ’0.5ļ·Æ + āˆ’0.5ļ·Æļ·®+ 0.5ļ·Æ + 2.5ļ·Æ + 2.5ļ·Æ+ 3.5ļ·Æ + 3.5ļ·Æ + 4.5ļ·Æ ļ·Æļ·Æļ·®12ļ·Æ = 3.5 + 2.5 + 2.5 + 1.5 + 0.5 + 0.5 + 0.5 + 2.5 + 2.5 + 3.5 + 3.5 + 4.5ļ·®12ļ·Æ = 28ļ·®12ļ·Æ = 2.33

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