Mean deviation about median - Ungrouped
Mean deviation about median - Ungrouped
Last updated at July 14, 2026 by Teachoo
Transcript
Ex 13.1, 3 Find the mean deviation about the median for the data. 13, 17, 16, 14, 11, 13, 10, 16, 11, 18, 12, 17 Arranging data in ascending order, 10, 11, 11, 12, 13, 13, 14, 16, 16, 17, 17, 18 Here, n = number of observations = 12 (even) Since n is even Median = šļ·®2ļ·Æļ·Æļ·®š”āļ·Æššš ššš£šš”ššš + šļ·®2ļ·Æ + 1ļ·Æļ·®š”āļ·Æššš ššš£šš”šššļ·®2ļ·Æ M = 12ļ·®2ļ·Æļ·Æļ·®š”āļ·Æššš ššš£šš”ššš + 12ļ·®2ļ·Æ + 1ļ·Æļ·®š”āļ·Æššš ššš£šš”šššļ·®2ļ·Æ M = 6ļ·®š”āļ·Æššš ššš£šš”ššš + 7ļ·®š”āļ·Æššš ššš£šš”šššļ·®2ļ·Æ M = 13 + 14ļ·®2ļ·Æ = 27ļ·®2ļ·Æ = 13.5 Thus, for 10, 11, 11, 12, 13, 13, 14, 16, 16, 17, 17, 18 Median = 13.5 Mean deviation about median = ﷮﷮ š„š āMļ·Æļ·Æļ·®12ļ·Æ = 10 ā 13.5ļ·Æ + 11 ā 13.5ļ·Æ + 11 ā 13.5ļ·Æ + 12 ā 13.5ļ·Æ + 13 ā 13.5ļ·Æ+ 13 ā 13.5ļ·Æļ·®+ 14 ā 13.5ļ·Æ + 16 ā 13.5ļ·Æ + 16 ā 13.5ļ·Æ + 17 ā 13.5ļ·Æ + 17 ā 13.5ļ·Æ+ 18 ā 13.5ļ·Æļ·Æļ·Æļ·®12ļ·Æ = ā3.5ļ·Æ + ā2.5ļ·Æ + ā2.5ļ·Æ + ā1.5ļ·Æ + ā0.5ļ·Æ + ā0.5ļ·Æļ·®+ 0.5ļ·Æ + 2.5ļ·Æ + 2.5ļ·Æ+ 3.5ļ·Æ + 3.5ļ·Æ + 4.5ļ·Æ ļ·Æļ·Æļ·®12ļ·Æ = 3.5 + 2.5 + 2.5 + 1.5 + 0.5 + 0.5 + 0.5 + 2.5 + 2.5 + 3.5 + 3.5 + 4.5ļ·®12ļ·Æ = 28ļ·®12ļ·Æ = 2.33