Example 5 - Chapter 13 Class 11 Statistics

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Example 5 - Find mean deviation about median - Chapter 15 - Mean deviation about median - Discrete Frequency

Example 5 - Chapter 15 Class 11 Statistics - Part 2

Transcript

Example 5 - Chapter 15 Class 11 Statistics - NCERT Find the mean deviation about the median for the following data: xi 3 6 9 12 13 15 21 22 fi 3 4 5 2 4 5 4 3 c.f is Cumulative frequency N = 29 (odd) ∴ Median = ((𝑁 + 1)/2)^π‘‘β„Žterm = ((29 + 1)/2)^π‘‘β„Ž term = (30/2)^π‘‘β„Ž term = 15th term Now, finding mean deviation about median As, 15th term lie in c.f of 21. Median = 30 βˆ‘128▒𝑓𝑖 = 29 βˆ‘128▒𝑓𝑖 |π‘₯𝑖 βˆ’M| = 148 ∴ Mean Deviation = (Ξ£ 𝑓_𝑖 |π‘₯_(𝑖 )βˆ’ M|)/𝑓_𝑖 = 148/29 = 5.1

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.