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Example 5 - Chapter 15 Class 11 Statistics - NCERT
Find the mean deviation about the median for the following data:
xi 3 6 9 12 13 15 21 22
fi 3 4 5 2 4 5 4 3
c.f is Cumulative frequency
N = 29 (odd)
β΄ Median = ((π + 1)/2)^π‘βterm
= ((29 + 1)/2)^π‘β term
= (30/2)^π‘β term
= 15th term
Now, finding mean deviation about median
As, 15th term lie in c.f of 21.
Median = 30
β128βππ = 29
β128βππ |π₯π βM| = 148
β΄ Mean Deviation = (Ξ£ π_π |π₯_(π )β M|)/π_π
= 148/29
= 5.1

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.

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