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Ex 13.1, 4 - Chapter 13 Class 11 Statistics
Last updated at August 17, 2026 by Teachoo
Mean deviation about median - Ungrouped
Chapter 13 Class 11 Statistics
Concept wise
- Mean deviation about mean - Ungrouped
- Mean deviation about mean - Discrete Frequency
- Mean deviation about mean - Continuous frequency distibution
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Mean deviation about median - Ungrouped
- Mean deviation about median - Discrete Frequency
- Mean deviation about median - Continuous frequency distibution
- Standard deviation and variance - Ungrouped data
- Standard deviation and variance - Discrete frequency (grouped data)
- Standard deviation and variance - Continuous frequency (grouped data)
- Co-efficient of variation
- Indirect questions - Multiplication of observation
- Indirect questions - finding remaining observations
- Indirect questions - Incorrect observation
Transcript
Ex15.1, 4 Find the mean deviation about the median for the data 36, 72, 46, 42, 60, 45, 53, 46, 51, 49 Arranging data in ascending order, 36, 42, 45, 46, 46, 49, 51, 53, 60, 72 Here, n = number of observations = 10 (even) Since n is even Median = (( /2)^ + ( /2 + 1)^ )/2 M = ((10/2)^ + (10/2 + 1)^ )/2 M = (5^ + 6^ )/2 M = (46 + 49)/2 = 95/2 = 47.5 Thus, for 36, 42, 45, 46, 46, 49, 51, 53, 60, 72 Median = 47.5 Mean deviation about median = ( 128 | M| )/10 M.D.(M) = (( (|36 47.5| + |42 47.5| + |45 47.5| + |46 47.5| + |46 47.5| @+ |49 47.5| + |51 47.5| + |53 47.5|+ |60 47.5| + |72 47.5| )))/10 = (( (| 11.5| + | 5.5| + | 2.5| + | 1.5| + | 1.5| @+ |1.5| + |3.5|+ |5.5| + |12.5| + |24.5| )))/10 = (11.5 + 5.5 +2.5 + 1.5 + 1.5 + 1.5 + 3.5 + 5.5 + 12.5 + 24.5)/10 = 70/10 = 7
