Example 5 - Find mean deviation about median - Chapter 15 - Mean deviation about median - Discrete Frequency

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  1. Chapter 15 Class 11 Statistics
  2. Serial order wise
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Example 5 - Chapter 15 Class 11 Statistics - NCERT Find the mean deviation about the median for the following data: xi 3 6 9 12 13 15 21 22 fi 3 4 5 2 4 5 4 3 c.f is Cumulative frequency N = 29 (odd) ∴ Median = ((𝑁 + 1)/2)^π‘‘β„Žterm = ((29 + 1)/2)^π‘‘β„Ž term = (30/2)^π‘‘β„Ž term = 15th term Now, finding mean deviation about median As, 15th term lie in c.f of 21. Median = 30 βˆ‘128▒𝑓𝑖 = 29 βˆ‘128▒𝑓𝑖 |π‘₯𝑖 βˆ’M| = 148 ∴ Mean Deviation = (Ξ£ 𝑓_𝑖 |π‘₯_(𝑖 )βˆ’ M|)/𝑓_𝑖 = 148/29 = 5.1

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