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Example 19 - Mean, standard deviation of 100 observations - Indirect questions - Incorrect observation

Example 19 - Chapter 15 Class 11 Statistics - Part 2
Example 19 - Chapter 15 Class 11 Statistics - Part 3 Example 19 - Chapter 15 Class 11 Statistics - Part 4 Example 19 - Chapter 15 Class 11 Statistics - Part 5

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Example 19 The mean and standard deviation of 100 observations were calculated as 40 and 5.1, respectively by a student who took by mistake 50 instead of 40 for one observation. What are the correct mean and standard deviation? Given that number of observations (n) = 100 Incorrect mean ( š‘„ļ·Æ ) = 40, Incorrect standard deviation (σ) = 5.1 We know that š‘„ļ·Æ = 1ļ·®š‘›ļ·Æ 40 = 1ļ·®100ļ·Æ 40 Ɨ 100 = 4000 = = 4000 ∓ Incorrect sum of observations = 4000 Finding correct sum of observations , 50 is taken in place of 40 So, Correct sum of observations = Incorrect sum – 50 + 40 = 4000 – 50 + 40 = 3990 Hence, Correct mean = Correct sum of observationsļ·®Number of observations ļ·Æ = 3990ļ·®100ļ·Æ = 39.9 Now, Incorrect Standard deviation (σ) = 1ļ·®Nļ·Æ ļ·®N Ɨ(š¼š‘›š‘š‘œš‘Ÿš‘Ÿš‘’š‘š‘” ﷮﷮xi2 ) – š¼š‘›š‘š‘œš‘Ÿš‘Ÿš‘’š‘š‘” ﷮﷮xiļ·Æļ·Æ2ļ·Æļ·Æ 5.1 = 1ļ·®100ļ·Æ ļ·®100(š¼š‘›š‘š‘œš‘Ÿš‘Ÿš‘’š‘š‘” ﷮﷮xi2 ) – š‘°š’š’„š’š’“š’“š’†š’„š’• ﷮﷮xiļ·Æļ·Æ2ļ·Æļ·Æ 5.1 Ɨ 100 = ļ·®100(š¼š‘›š‘š‘œš‘Ÿš‘Ÿš‘’š‘š‘” ﷮﷮xi2 ) – šŸ’šŸŽšŸŽšŸŽļ·Æ2ļ·Æļ·Æ 510 = ļ·®100(š¼š‘›š‘š‘œš‘Ÿš‘Ÿš‘’š‘š‘” ﷮﷮xi2 ) – 4000ļ·Æ2ļ·Æļ·Æ Squaring both sides (510)2 = ļ·®100(š¼š‘›š‘š‘œš‘Ÿš‘Ÿš‘’š‘š‘” ﷮﷮xi2 )– 4000ļ·Æ2ļ·Æļ·Æļ·Æļ·®2ļ·Æ 260100= 100(š¼š‘›š‘š‘œš‘Ÿš‘Ÿš‘’š‘š‘” ﷮﷮xi2 )– 4000ļ·Æ2ļ·Æ 260100= 100(š¼š‘›š‘š‘œš‘Ÿš‘Ÿš‘’š‘š‘” ﷮﷮xi2 ) –﷯ 16000000 260100 + 16000000 = 100(š¼š‘›š‘š‘œš‘Ÿš‘Ÿš‘’š‘š‘” ﷮﷮xi2 ) ļ·Æ 16260100 = 100(š¼š‘›š‘š‘œš‘Ÿš‘Ÿš‘’š‘š‘” ﷮﷮xi2 ) ļ·Æ 100(š¼š‘›š‘š‘œš‘Ÿš‘Ÿš‘’š‘š‘” ﷮﷮xi2 ) ļ·Æ = 16260100 š¼š‘›š‘š‘œš‘Ÿš‘Ÿš‘’š‘š‘” ﷮﷮xi2 ļ·Æ = 1ļ·®100ļ·Æ Ɨ 16260100 š¼š‘›š‘š‘œš‘Ÿš‘Ÿš‘’š‘š‘” ﷮﷮xi2 ļ·Æ = 162601 Since 50 is removed and 40 is added, So, (š‘Ŗš’š’“š’“š’†š’„š’• ﷮﷮xi2 ) ļ·Æ = 162601 – (50)2 + (40)2 = 162601 – 2500 + 1600 = 161701 Now, Correct Standard deviation (σ) = 1ļ·®Nļ·Æ ļ·®N Ɨ(š¶š‘œš‘Ÿš‘Ÿš‘’š‘š‘” ﷮﷮xi2 )– š¶š‘œš‘Ÿš‘Ÿš‘’š‘š‘” ﷮﷮xiļ·Æļ·Æ2ļ·Æļ·Æ = 1ļ·®100ļ·Æ ļ·®100 161701ļ·Æ āˆ’ 3990ļ·Æ2ļ·Æ = 1ļ·®100ļ·Æ ļ·®16170100 āˆ’15920100ļ·Æ = 1ļ·®100ļ·Æ ļ·®250000ļ·Æ = 1ļ·®100ļ·Æ ļ·® 500ļ·Æ2ļ·Æ = 1ļ·®100ļ·Æ Ɨ 500 = 5 Hence, Correct mean = 39.9 & Correct standard deviation = 5

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.