Example 3 - Chapter 15 Class 11 Statistics (Term 1)
Last updated at Sept. 6, 2021 by Teachoo
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Example 6 (Normal Method)
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Example 13 Deleted for CBSE Board 2022 Exams
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Chapter 15 Class 11 Statistics (Term 1)
Serial order wise
- Ex 15.1
- Ex 15.2
- Ex 15.3
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- Miscellaneous
Transcript
Example 3 Find the mean deviation about the median for the following data: 3, 9, 5, 3, 12, 10, 18, 4, 7, 19, 21. Arranging data in ascending order, 3, 3, 4, 5, 7, 9, 10, 12, 18, 19, 21 Here, number of observations = n = 11 (odd). Since n is odd, Median = ( 11 + 12)th observation M = ( 122)th observation = 6th observation = 9 Now, we calculate mean deviation about median 3, 3, 4, 5, 7, 9, 10, 12, 18, 19, 21 Median (M) = 9 Mean deviation about median = 𝑥𝑖 −M11 M.D.(M) = 3 − 9 + 3 − 9 + 4 − 9 + 5 − 9 + 7 − 9 + 9 − 9 + 10 − 9 + 12 − 9+ 18 − 9 + 19 − 9 + 21 − 9 11 = −6 + −6 + −5 + −4 + −2 + 0 + 1 + 3+ 9 + 10 + 12 11 = 6 + 6 + 5 + 4 + 2 + 0 + 1 + 3 + 9 + 10 + 1211 = 5811 = 5.27
