
Examples
Example 2
Example 3 Important You are here
Example 4
Example 5 Important
Example 6 (Normal Method)
Example 6 (Shortcut Method) Important
Example 7 Important
Example 8
Example 9 Important
Example 10 Important
Example 11
Example 12 Important
Example 13 Deleted for CBSE Board 2022 Exams
Example 14 Important
Example 15 Important Deleted for CBSE Board 2022 Exams
Example 16
Example 17 Important
Example 18
Example 19 Important
Examples
Last updated at Sept. 6, 2021 by Teachoo
Example 3 Find the mean deviation about the median for the following data: 3, 9, 5, 3, 12, 10, 18, 4, 7, 19, 21. Arranging data in ascending order, 3, 3, 4, 5, 7, 9, 10, 12, 18, 19, 21 Here, number of observations = n = 11 (odd). Since n is odd, Median = ( 11 + 12)th observation M = ( 122)th observation = 6th observation = 9 Now, we calculate mean deviation about median 3, 3, 4, 5, 7, 9, 10, 12, 18, 19, 21 Median (M) = 9 Mean deviation about median = 𝑥𝑖 −M11 M.D.(M) = 3 − 9 + 3 − 9 + 4 − 9 + 5 − 9 + 7 − 9 + 9 − 9 + 10 − 9 + 12 − 9+ 18 − 9 + 19 − 9 + 21 − 9 11 = −6 + −6 + −5 + −4 + −2 + 0 + 1 + 3+ 9 + 10 + 12 11 = 6 + 6 + 5 + 4 + 2 + 0 + 1 + 3 + 9 + 10 + 1211 = 5811 = 5.27