Ex 7.7, 11 - Integrate root x2 - 8x + 7 dx - Class 12 - Ex 7.7

Ex 7.7, 11 - Chapter 7 Class 12 Integrals - Part 2

Remove Ads Share on WhatsApp

Transcript

Ex 7.7, 11 ∫1ā–’ć€–āˆš(š‘„2 āˆ’8š‘„+7) " " 怗 š‘‘š‘„ 1/2 (x - 4)√(š‘„2 āˆ’8š‘„+7) + 9 log |š‘„āˆ’4+√(š‘„2āˆ’8š‘„+7)| + C 1/2 (x + 4)√(š‘„2 āˆ’8š‘„+7) + 9 log |š‘„+4+√(š‘„2āˆ’8š‘„+7)| + C 1/2 (x - 4)√(š‘„2 āˆ’8š‘„+7) - 3√2 log |š‘„āˆ’4+√(š‘„2āˆ’8š‘„+7)| + C 1/2 (x - 4)√(š‘„2 āˆ’8š‘„+7) + 9/2 log |š‘„āˆ’4+√(š‘„2āˆ’8š‘„+7)| + C ∫1ā–’ć€–āˆš(š‘„^2āˆ’8š‘„+7) š‘‘š‘„ć€— =∫1ā–’ć€–āˆš(š‘„^2āˆ’2(4)(š‘„)+7) š‘‘š‘„ć€— =∫1ā–’ć€–āˆš(š‘„^2āˆ’2(4)(š‘„) 怖+(4)怗^2āˆ’(4)^2+7) š‘‘š‘„ć€— =∫1ā–’ć€–āˆš((š‘„āˆ’4)^2āˆ’16+7) š‘‘š‘„ć€— =∫1ā–’ć€–āˆš((š‘„āˆ’4)^2āˆ’9 ) š‘‘š‘„ć€— =∫1ā–’ć€–āˆš((š‘„āˆ’4)^2āˆ’(3)^2 ) š‘‘š‘„ć€— =(š‘„ āˆ’ 4)/2 √((š‘„āˆ’4)^2āˆ’(3)^2 )āˆ’(3)^2/2 š‘™š‘œš‘”|š‘„āˆ’4+√((š‘„āˆ’4)^2āˆ’(3)^2 )|+š¶ =(š‘„ āˆ’ 4)/2 √(š‘„^2āˆ’8š‘„+16āˆ’9 )āˆ’9/2 š‘™š‘œš‘”|š‘„āˆ’4+√(š‘„^2āˆ’8š‘„+16āˆ’9)|+š¶ =(š‘„ āˆ’ 4)/2 √(š‘„^2āˆ’8š‘„+7)āˆ’9/2 š‘™š‘œš‘”|š‘„āˆ’4+√(š‘„^2āˆ’8š‘„+7)|+š¶ ∓ Option (D) is correct. It is of the form ∫1ā–’ć€–āˆš(š‘„^2āˆ’š‘Ž^2 ) š‘‘š‘„=š‘„/2 √(š‘„^2āˆ’š‘Ž^2 )āˆ’š‘Ž^2/2 š‘™š‘œš‘”|š‘„+√(š‘„^2āˆ’š‘Ž^2 )|+š¶ć€— ∓ Replacing š‘„ by š‘„āˆ’4 and a by 3 , we get

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh is an IIT Kanpur graduate and has been teaching for 16+ years. At Teachoo, he breaks down Maths, Science and Computer Science into simple steps so students understand concepts deeply and score with confidence.

Many students prefer Teachoo Black for a smooth, ad-free learning experience.