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Ex 8.2

Ex 8.2,1
Important
Deleted for CBSE Board 2022 Exams

Ex 8.2, 2 Deleted for CBSE Board 2022 Exams

Ex 8.2, 3 Important Deleted for CBSE Board 2022 Exams

Ex 8.2, 4 Important Deleted for CBSE Board 2022 Exams

Ex 8.2, 5 Important Deleted for CBSE Board 2022 Exams

Ex 8.2, 6 (MCQ) Deleted for CBSE Board 2022 Exams You are here

Ex 8.2 , 7 (MCQ) Important Deleted for CBSE Board 2022 Exams

Chapter 8 Class 12 Application of Integrals (Term 2)

Serial order wise

Last updated at Aug. 11, 2021 by Teachoo

Ex 8.2 , 6 Smaller area enclosed by the circle ๐ฅ2+๐ฆ2 =4 and the line ๐ฅ+๐ฆ=2 is (A) 2 (ฯ โ 2) (B) ฯ โ 2 (C) 2ฯ โ 1 (D) 2 (ฯ + 2) Step 1: Drawing figure Circle is ๐ฅ2+๐ฆ2 =4 (๐ฅโ0)2+(๐ฆโ0)2 = 2๏ทฎ2๏ทฏ So, Center = (0, 0) & Radius = 2 Also, ๐ฅ+๐ฆ=2 passes through (0, 2) & (2, 0) Hence, intersecting points A = (2, 0) & B = (0, 2) Thus, Area required = Area OACB โ AREA OAB = ๐ โ 2 Thus, Option (B) is correct.