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Last updated at May 29, 2018 by Teachoo
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Ex 8.2 , 6 Smaller area enclosed by the circle ๐ฅ2+๐ฆ2 =4 and the line ๐ฅ+๐ฆ=2 is (A) 2 (ฯ โ 2) (B) ฯ โ 2 (C) 2ฯ โ 1 (D) 2 (ฯ + 2) Step 1: Drawing figure Circle is ๐ฅ2+๐ฆ2 =4 (๐ฅโ0)2+(๐ฆโ0)2 = 2๏ทฎ2๏ทฏ So, Center = (0, 0) & Radius = 2 Also, ๐ฅ+๐ฆ=2 passes through (0, 2) & (2, 0) Hence, intersecting points A = (2, 0) & B = (0, 2) Thus, Area required = Area OACB โ AREA OAB = ๐ โ 2 Thus, Option (B) is correct.
Ex 8.2
Ex 8.2, 2 Not in Syllabus - CBSE Exams 2021
Ex 8.2, 3 Important Not in Syllabus - CBSE Exams 2021
Ex 8.2, 4 Important Not in Syllabus - CBSE Exams 2021
Ex 8.2, 5 Important Not in Syllabus - CBSE Exams 2021
Ex 8.2, 6 Not in Syllabus - CBSE Exams 2021 You are here
Ex 8.2 , 7 Not in Syllabus - CBSE Exams 2021
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