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Question · Revise, Reflect, Refine, Q11, page 113
The velocity-time graph of an object of mass 10 kg moving along a straight line is shown in Fig. 6.41. Calculate the force acting on the object by using the graph.
![Question 11 — The velocity-time - How Forces Affect Moti - [Teachoo] - Questions at the end of the chapter](https://cdn.teachoo.com/4304c117-3f7f-4840-9e47-ba2d8878155b/animation-for-the-velocity-time-graph-of-an-object-of-mass-10-kg-moving-along-a-straight-line-is-shown-in-fig.-6.41.-ca.gif)
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Answer
- From the graph, the velocity is 10 m s⁻¹ at t = 0 s and 30 m s⁻¹ at t = 8 s.
- Acceleration, a = (v − u) / t = (30 − 10) / 8 = 2.5 m s⁻²
- Force, F = ma = 10 kg × 2.5 m s⁻² = 25 N
- Answer: 25 N, acting in the direction of motion.
