1. Chapter 2 Class 12 Inverse Trigonometric Functions (Term 1)
  2. Concept wise
  3. Formulae based

Ex 2.2, 14 - Chapter 2 Class 12 Inverse Trigonometric Functions (Term 1)

Last updated at May 12, 2021 by

Ex 2.2, 14 - If sin (sin-1 1/5 + cos-1 x) = 1, find x - CBSE

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Ex 2.2, 14 - Chapter 2 Class 12 Inverse Trigonometric Functions - Part 2

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  1. Chapter 2 Class 12 Inverse Trigonometric Functions (Term 1)
  2. Concept wise

    3. Formulae based

    Changing of trignometric variables and then applying formula →

Transcript

Ex 2.2, 14 If sin ("sin−1 " 1/5 " + cos−1 x" ) = 1 , then find the value of x. Given sin ("sin−1 " 1/5 " + cos−1 x" ) = 1 Putting sin 𝜋/2 = 1 sin ("sin−1 " 1/5 " + cos−1 x" ) = sin π/2 Comparing angles "sin−1 " 1/5 + "cos−1 x" = 𝜋/2 "sin−1 " 1/5 = 𝝅/𝟐 – "cos−1 x" We know that sin"−"1 x + cos"−"1 x = 𝜋/2 sin"−"1 x = 𝜋/2 – cos"−"1 x sin-1 1/5 = sin"−"1 x Thus, we can write 1/5 = x x = 𝟏/𝟓 Hence, x = 1/5

Chapter 2 Class 12 Inverse Trigonometric Functions (Term 1)
Concept wise

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