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Example 3 (i) Important Deleted for CBSE Board 2023 Exams
Ex 2.2,1 Deleted for CBSE Board 2023 Exams
Ex 2.2, 2 Important Deleted for CBSE Board 2023 Exams
Example 8 Deleted for CBSE Board 2023 Exams
Ex 2.2, 12 Important Deleted for CBSE Board 2023 Exams
Ex 2.2, 14 Important Deleted for CBSE Board 2023 Exams You are here
Example 4 Deleted for CBSE Board 2023 Exams
Ex 2.2, 3 Deleted for CBSE Board 2023 Exams
Misc. 8 Important Deleted for CBSE Board 2023 Exams
Ex 2.2, 4 Important Deleted for CBSE Board 2023 Exams
Ex 2.2, 15 Important Deleted for CBSE Board 2023 Exams
Example 13 Important Deleted for CBSE Board 2023 Exams
Misc. 14 Deleted for CBSE Board 2023 Exams
Misc 17 (MCQ) Deleted for CBSE Board 2023 Exams
Misc. 13 Important Deleted for CBSE Board 2023 Exams
Example 10 Important Deleted for CBSE Board 2023 Exams
Misc. 3 Deleted for CBSE Board 2023 Exams
Misc. 4 Important Deleted for CBSE Board 2023 Exams
Misc 12 Important Deleted for CBSE Board 2023 Exams
Misc 16 (MCQ) Important Deleted for CBSE Board 2023 Exams
Last updated at May 12, 2021 by Teachoo
Ex 2.2, 14 If sin ("sin−1 " 1/5 " + cos−1 x" ) = 1 , then find the value of x. Given sin ("sin−1 " 1/5 " + cos−1 x" ) = 1 Putting sin 𝜋/2 = 1 sin ("sin−1 " 1/5 " + cos−1 x" ) = sin π/2 Comparing angles "sin−1 " 1/5 + "cos−1 x" = 𝜋/2 "sin−1 " 1/5 = 𝝅/𝟐 – "cos−1 x" We know that sin"−"1 x + cos"−"1 x = 𝜋/2 sin"−"1 x = 𝜋/2 – cos"−"1 x sin-1 1/5 = sin"−"1 x Thus, we can write 1/5 = x x = 𝟏/𝟓 Hence, x = 1/5