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  1. Chapter 16 Class 11 Probability
  2. Serial order wise

Transcript

Example 10 One card is drawn from a well shuffled deck of 52 cards. If each outcome is equally likely, calculate the probability that card will be a diamond Since there 52 cards n(S) = Total number of cards = 52 There are 13 diamond cards Let A be event that diamond card is withdrawn So, n(A) = 13 Probability of A = P(A) = (๐‘๐‘ข๐‘š๐‘๐‘’๐‘Ÿ ๐‘œ๐‘“ ๐‘‘๐‘–๐‘Ž๐‘š๐‘œ๐‘›๐‘‘ ๐‘๐‘Ž๐‘Ÿ๐‘‘๐‘ )/(๐‘‡๐‘œ๐‘ก๐‘Ž๐‘™ ๐‘›๐‘ข๐‘š๐‘๐‘’๐‘Ÿ ๐‘œ๐‘“ ๐‘๐‘Ž๐‘Ÿ๐‘‘๐‘ ) = (n(A))/(n(S)) = 13/52 = ๐Ÿ/๐Ÿ’ Example 10 One card is drawn from a well shuffled deck of 52 cards. If each outcome is equally likely, calculate the probability that card will be (ii) not an ace There are 4 ace cards Let B be the event that card drawn is ace So, n(B) = 4 Hence Probability card drawn is ace = P(B) = (๐‘๐‘ข๐‘š๐‘๐‘’๐‘Ÿ ๐‘œ๐‘“ ๐‘Ž๐‘๐‘’ ๐‘๐‘Ž๐‘Ÿ๐‘‘๐‘ )/(๐‘‡๐‘œ๐‘ก๐‘Ž๐‘™ ๐‘›๐‘ข๐‘š๐‘๐‘’๐‘Ÿ ๐‘œ๐‘“ ๐‘๐‘Ž๐‘Ÿ๐‘‘๐‘ ) = (n(A))/(n(S)) = 4/52 = 1/13 Probability that card is not an ace = P(Bโ€™) = 1 โ€“ P(B) = 1 โ€“ 1/13 = (13 โˆ’ 1)/13 = ๐Ÿ๐Ÿ/๐Ÿ๐Ÿ‘ Example 10 One card is drawn from a well shuffled deck of 52 cards. If each outcome is equally likely, calculate the probability that card will be (iii) a black card (i.e., a club or, a spade) There are 26 black cards (13 spade and 13 club) Let C be the probability that card drawn is black n(C) = 13 + 13 = 26 Hence Probability card drawn is black = P(C) = (๐‘๐‘ข๐‘š๐‘๐‘’๐‘Ÿ ๐‘œ๐‘“ ๐‘๐‘™๐‘Ž๐‘๐‘˜ ๐‘๐‘Ž๐‘Ÿ๐‘‘๐‘ )/(๐‘‡๐‘œ๐‘ก๐‘Ž๐‘™ ๐‘›๐‘ข๐‘š๐‘๐‘’๐‘Ÿ ๐‘œ๐‘“ ๐‘๐‘Ž๐‘Ÿ๐‘‘๐‘ ) = (n(C))/(n(S)) = 26/52 = ๐Ÿ/๐Ÿ Example 10 One card is drawn from a well shuffled deck of 52 cards. If each outcome is equally likely, calculate the probability that card will be (iv) not a diamond From part (i) , A is the event that card is diamond So, Aโ€™ is event that card is not diamond Probability card is not a diamond = P(Aโ€™) = 1 โ€“ P(A) = 1 โ€“ 1/4 = (4 โˆ’ 1)/4 = ๐Ÿ‘/๐Ÿ’ Example 10 One card is drawn from a well shuffled deck of 52 cards. If each outcome is equally likely, calculate the probability that card will be (v) not a black card From part (iii) , C is the event that card is black So, Cโ€™ is event that card is not black Probability card is not a black = P(Cโ€™) = 1 โ€“ P(C) = 1 โ€“ 1/2 = ๐Ÿ/๐Ÿ

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Davneet Singh's photo - Teacher, Computer Engineer, Marketer
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.