Last updated at May 29, 2018 by Teachoo

Transcript

Example, 8 A coin is tossed three times, consider the following events. A: No head appears , B: Exactly one head appears and C: At least two heads appear . Do they form a set of mutually exclusive and exhaustive events? If 3 coins are tossed , possible outcomes are S = {HHH, HHT, HTH, THH, HTT, THT, TTH, TTT} A: no head appear Hence only tail appear in all 3 times So A = {TTT} B: exactly one head appear B = {HTT, THT, TTH} C: at least two heads appear C = {HHT, HTH, THH, HHH} A = {TTT} B = {HTT, THT, TTH} C = {HHT, HTH, THH, HHH} A B C = {TTT, HTT, THT, TTH, HHT, HTH, THH, HHH} = S Hence A, B and C are exhaustive events. Now A B = {TTT} {HTT, THT, TTH} = There is no common elements in A & B So, A & B are mutually exclusive A C = {TTT} {HHT, HTH, THH, HHH} = There is no common elements in A & C Hence A & C are mutually exclusive B C = {HTT, THT, TTH} {HHT, HTH, THH, HHH} = There is no common element in B & C Hence B & C are mutually exclusive Since A & B, A & C, B & C are mutually exclusive Hence A, B and C are mutually exclusive Hence, A, B and C form a set of mutually exclusive and exhaustive events.

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.