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Area of Parallelogram for Different Heights & Base
Last updated at March 16, 2026 by Teachoo
Area of Parallelogram
Area of Parallelogram
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Class 8 (Ganita Prakash - 1, 2 & Old NCERT)
Chapter 7 Class 8 - Area (Ganita Prakash II)
- Area of Rectangle and Square
- Perimeter vs Area
- Figure it out - Page 150-152
- Area of Triangle
- Applications of Area of Triangle Formula
- Triangles between Parallel Lines with a Common Base
- Figure it out - Page 157-159
- Area of any Polygon
- Figure it out - Page 160
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Area of Parallelogram
- Area of Rhombus
- Area of Trapezium
- Figure it out - Page 169-170
- Areas in Real Life
Transcript
Area of Parallelogram for Different Heights & BaseWe know that Area of Parallelogram = Base × Height Let’s try to find Area of Parallelogram when Different Heights & Base are given, like Base = b = AB Height = h = DE Area of Parallelogram = b × h = AB × DE Base = b = AB Height = h = CE Area of Parallelogram = b × h = AB × CE Base = b = BC Height = h = DE Area of Parallelogram = b × h = BC × DE Base = b = BC Height = h = AE Area of Parallelogram = b × h = BC × AE Let’s take some examples, Find area of parallelogram Base = b = AD = 4 m Height = h = BF = 4.5 m Area of parallelogram = b × h = 4 × 4.5 = 18 m2 Find area of parallelogram Base = b = AD = BC = 4.5 m Height = h = BF = 4 cm Area of parallelogram = b × h = 4.5 × 4 = 18 cm2
