Question 1 - Page 110 - Mean and Median with Frequencies - Chapter 5 Class 8 - Tales by Dots and Lines (Ganita Prakash II)

Last updated at August 14, 2026 by

What is the average family size of this class? [Class 8 Ganita Prakash - Mean and Median with Frequencies

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Question 1 - Page 110 What is the average family size of this class?Now, Mean = (๐‘†๐‘ข๐‘š ๐‘œ๐‘“ ๐‘‚๐‘๐‘ ๐‘’๐‘Ÿ๐‘ฃ๐‘Ž๐‘ก๐‘–๐‘œ๐‘›๐‘ )/(๐‘๐‘ข๐‘š๐‘๐‘’๐‘Ÿ ๐‘œ๐‘“ ๐‘‚๐‘๐‘ ๐‘’๐‘Ÿ๐‘ฃ๐‘Ž๐‘ก๐‘–๐‘œ๐‘›๐‘ ) Since there are frequencies, we take those into account So, our Mean becomes Mean = (๐Ÿ‘ ร— ๐Ÿ‘ + ๐Ÿ’ ร— ๐Ÿ๐Ÿ + ๐Ÿ“ ร— ๐Ÿ— + ๐Ÿ” ร— ๐Ÿ• + ๐Ÿ– ร— ๐Ÿ + ๐Ÿ— ร— ๐Ÿ + ๐Ÿ๐ŸŽ ร— ๐Ÿ)/(๐Ÿ‘ + ๐Ÿ๐Ÿ + ๐Ÿ— + ๐Ÿ• + ๐Ÿ‘ + ๐Ÿ + ๐Ÿ + ๐Ÿ) = (9 + 44 + 45 + 42 + 8 + 9 + 10)/36 = 188/36 = 5.22 (approx.)

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