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Question 2 - Figure it out - Page 50 - Chapter 2 Class 8 - The Baudhayana-Pythagoras Theorem (Ganita Part 2)
Last updated at February 23, 2026 by Teachoo
Figure it out - Page 50
Class 8 (Ganita Prakash - 1, 2 & Old NCERT)
Chapter 2 Class 8 - The Baudhayana-Pythagoras Theorem (Ganita Part 2)
- Doubling a square
- Halving a square
- Hypotenuse of an Isosceles Right Triangle
- Decimal Representation of √2
- Figure it out - Page 39, 40
- Formula for Hypotenuse of an Isosceles Right Triangle
- Combining Two squares
- Baudhāyana’s Theorem on Right-angled triangles
- Pythagorean triples
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Figure it out - Page 50
- A Long-Standing Open Problem
- Further Applications of the Baudhāyana - Pythagoras Theorem
- Figure it out - Page 52, 53, 54
Transcript
Question 2 Does this method yield non-primitive Baudhāyana triples? [Hint: Observe that among the triples generated, one of the smaller sidelengths is one less than the hypotenuse.]No, it never yields non-primitive triples. Let’s look at the generated triples – example (7, 24, 25) The hypotenuse (𝑛) and one of the legs (𝑛−1) are consecutive integers (like 24 and 25 ). Consecutive integers never share a common factor other than 1 . Because two of the three numbers share no common factors, it is impossible for all three to share a common factor. Therefore, the triple is always primitive.
