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Question 1 - Figure it out (Page 142) - Construction Methods in Åulba-SÅ«tras - Chapter 6 Class 7 - Constructions and Tilings (Ganita Prakash II)
Last updated at August 14, 2026 by Teachoo
Class 7 (Ganita Prakash 1, 2)
Chapter 6 Class 7 - Constructions and Tilings (Ganita Prakash II)
- Constructing an Eye
- Constructing a Perpendicular Bisector
- Constructing angle 90°
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Construction Methods in Åulba-SÅ«tras
- Constructing Angle Bisectors
- Figure it out - Pag 144, 145
- Constructing Copy of an Angle
- Construction of a Line Parallel to the Given Line
- Constructing Arch Designs
- Constructing Regular Hexagon, Angle 60° and 6-pointed Star
- Figure it out - Pag 154, 155
- Tangrams
- Tiling
- Figure it out - Page 160
- Tiling the Entire Plane
Transcript
Question 1 - Figure it out (Page 142) Justify why AB in Fig. 6.4 is the perpendicular bisectorThink about Symmetry: When you pulled the rope tight to make Point A, the rope length on the left (from ð to ðŽ ) was exactly the same as the rope length on the right (from ð to ðŽ ). This created a perfectly balanced Triangle (an isosceles triangle). The same thing happened at the bottom for Point B. Because A and B are both perfectly balanced between X and Y , the line connecting them must go straight down the middle! In geometry, the line connecting the tips of two back-to-back isosceles triangles (a kite shape) always crosses the middle at 90^â. Thus, AB is Mid-point of XY Crosses at 90° ⎠AB is the perpendicular bisector
