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Constructing a Perpendicular Bisector
Last updated at February 6, 2026 by Teachoo
Class 7 (Ganita Prakash 1, 2 & old NCERT)
Chapter 6 Class 7 - Constructions and Tilings (Ganita Prakash II)
- Constructing an Eye
-
Constructing a Perpendicular Bisector
- Constructing angle 90°
- Construction Methods in Śulba-Sūtras
- Constructing Angle Bisectors
- Figure it out - Pag 144, 145
- Constructing Copy of an Angle
- Construction of a Line Parallel to the Given Line
- Constructing Arch Designs
- Constructing Regular Hexagon, Angle 60° and 6-pointed Star
- Figure it out - Pag 154, 155
- Tangrams
- Tiling
- Figure it out - Page 160
- Tiling the Entire Plane
Transcript
Perpendicular BisectorAB is the perpendicular bisector of XY Which means Perpendicular to XY, AB ⊥ XY O is the mid-point of XY, i.e. OX = OY Constructing a Perpendicular BisectorLet’s make a perpendicular bisector of Line XY Steps of Construction 1. Construct line segment XY of any length 2. Taking X as center, and radius more than 1/2 XY, draw arcs on top and bottom of XY 3. Taking Y as center, and radius same as before draw arcs on top and bottom of XY 4. Points where the arcs intersect is A & B 5. Join AB 6. Mark point O where AB intersects XY Here, AB is called the perpendicular bisector of XY It is Perpendicular to XY, AB ⊥ XY O is the mid-point of XY Let’s look at its definition and prove triangles congruent
