Get live Maths 1-on-1 Classs - Class 6 to 12
Ex 11.2
Last updated at March 22, 2023 by Teachoo
Ex 11.2, 12 Find the equation of the parabola that satisfies the following conditions: Vertex (0, 0) passing through (5, 2) and axis is along y-axis Given that axis is along the y-axis, So, equation of parabola is of the form x2 = 4ay or x2 = −4ay Plotting point (5, 2) Since point lie of the 1st quadrant & parabola passes through the point (5, 2) So, the parabola is of the form Hence equation of parabola is x2 = 4ay Point (5, 2) will satisfy the equation of parabola Putting x = 5 & y = 2 in (1) (5)2 = 4a(2) 25 = 8a 8a = 25 a = 𝟐𝟓/𝟖 Hence equation of parabola is x2 = 4ay Putting value of a = 25/8 x2 = 4(25/8)y x2 = 𝟐𝟓/𝟐 𝐲