Ex 11.2, 12 - Find parabola: Vertex (0, 0) passing (5, 2)  - Parabola - Basic Questions

  1. Chapter 11 Class 11 Conic Sections
  2. Serial order wise
Ask Download

Transcript

Ex 11.2, 12 Find the equation of the parabola that satisfies the following conditions: Vertex (0, 0) passing through (5, 2) and axis is along y-axis Given that axis is along the y-axis, So, equation of parabola is of the form x2 = 4ay or x2 = 4ay Plotting point (5, 2) Since point lie of the 1st quadrant & parabola passes through the point (5, 2) So, the parabola is of the form Hence equation of parabola is x2 = 4ay Point (5, 2) will satisfy the equation of parabola Putting x = 5 & y = 2 in (1) (5)2 = 4a(2) 25 = 8a 8a = 25 a = Hence equation of parabola is x2 = 4ay Putting value of a = 25 8 x2 = 4 25 8 y x2 =

About the Author

Davneet Singh's photo - Teacher, Computer Engineer, Marketer
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.