![Slide30.JPG](https://d1avenlh0i1xmr.cloudfront.net/3c2fbc39-a09d-4cf4-ac74-2f9427948ff0/slide30.jpg)
![Slide31.JPG](https://d1avenlh0i1xmr.cloudfront.net/56fdda5b-0234-44f1-99ca-ae5da97031ed/slide31.jpg)
Ex 10.2
Last updated at April 17, 2024 by Teachoo
Ex 10.2, 12 Find the equation of the parabola that satisfies the following conditions: Vertex (0, 0) passing through (5, 2) and axis is along y-axis Given that axis is along the y-axis, So, equation of parabola is of the form x2 = 4ay or x2 = −4ay Plotting point (5, 2) Since point lie of the 1st quadrant & parabola passes through the point (5, 2) So, the parabola is of the form Hence equation of parabola is x2 = 4ay Point (5, 2) will satisfy the equation of parabola Putting x = 5 & y = 2 in (1) (5)2 = 4a(2) 25 = 8a 8a = 25 a = 𝟐𝟓/𝟖 Hence equation of parabola is x2 = 4ay Putting value of a = 25/8 x2 = 4(25/8)y x2 = 𝟐𝟓/𝟐 𝐲