Ex 11.2, 2 - x2 = 6y, find focus, axis, directrix, latus

Ex 11.2,  2 - Chapter 11 Class 11 Conic Sections - Part 2
Ex 11.2,  2 - Chapter 11 Class 11 Conic Sections - Part 3

  1. Chapter 11 Class 11 Conic Sections (Term 2)
  2. Serial order wise

Transcript

Ex 11.2, 2 Find the coordinates of the focus, axis of the parabola, the equation of directrix and the length of the latus rectum for x2 = 6y Given equation is x2 = 6y Since the above equation is involves x2 Its axis is y-axis Also coefficient of x is positive (+1) Hence we use equation x2 = 4ay Comparing x2 = 6y & x2 = 4ay Comparing (1) & (2) 4ay = 6y a = 6๐‘ฆ/4๐‘ฆ a = 3/2 Coordinate of focus is (0, a) i.e. Focus ("0, " ๐Ÿ‘/๐Ÿ) Equation of Directix is y = โ€“a y = (โˆ’๐Ÿ‘)/๐Ÿ Latus Rectum is 4a = 4 ร— 3/2 = 2(3) = 6

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.