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Last updated at Feb. 6, 2020 by Teachoo
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Ex 11.2, 2 Find the coordinates of the focus, axis of the parabola, the equation of directrix and the length of the latus rectum for x2 = 6y Given equation is x2 = 6y Since the above equation is involves x2 Its axis is y-axis Also coefficient of x is positive (+1) Hence we use equation x2 = 4ay Comparing x2 = 6y & x2 = 4ay Comparing (1) & (2) 4ay = 6y a = 6๐ฆ/4๐ฆ a = 3/2 Coordinate of focus is (0, a) i.e. Focus ("0, " ๐/๐) Equation of Directix is y = โa y = (โ๐)/๐ Latus Rectum is 4a = 4 ร 3/2 = 2(3) = 6
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