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Ex 11.2, 8 - Find equation of parabola: Focus (0, -3), y = 3

Ex 11.2,  8 - Chapter 11 Class 11 Conic Sections - Part 2

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Ex 11.2, 8 Find the equation of the parabola that satisfies the following conditions: Focus (0, –3); directrix y = 3 Since focus lies on y-axis Hence equation is either x2 = 4ay & x2 = −4ay Now focus has a negative y co-ordinate So, we have to use equation x2 = −4ay Coordinate of focus = (0, −a) (0, −a) = (0, −3) −a = −3 a = 3 Equation of parabola is x2 = −4ay x2 = −4(3)y x2 = −12y

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