Ex 10.2, 10 - Chapter 10 Class 11 Conic Sections
Last updated at April 17, 2024 by Teachoo
Ex 10.2
Last updated at April 17, 2024 by Teachoo
Ex 10.2, 10 Find the equation of the parabola that satisfies the following conditions: Vertex (0, 0) focus (–2, 0) Since focus lies on y-axis Hence equation is either y2 = 4ax & y2 = −4ax Now focus has a negative y co-ordinate So, we have to use equation y2 = −4ax Coordinate of focus = (−a, 0) (−a, 0) = (−2, 0) −a = −2 a = 2 Equation of parabola is y2 = −4ax y2 = −4(2)x y2 = −8x