[Maths] Consider any 2 by 2 square of numbers in a calendar as shown - Figure it out - Page 154-156

part 2 - Question 4 - Figure it out - Page 154-156 - Chapter 6 Class 8 - We Distribute yet things Multiply (Ganita Prakash) - Class 8 (Ganita Prakash - 1, 2 & Old NCERT)
part 3 - Question 4 - Figure it out - Page 154-156 - Chapter 6 Class 8 - We Distribute yet things Multiply (Ganita Prakash) - Class 8 (Ganita Prakash - 1, 2 & Old NCERT)

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Question 4 Consider any 2 by 2 square of numbers in a calendar, as shown in the figure. Find products of numbers lying along each diagonal — 4 × 12 = 48, 5 × 11 = 55. Do this for the other 2 by 2 squares. What do you observe about the diagonal products? Explain why this happens. Hint: Label the numbers in each 2 by 2 square asOur hint shows a general 2 × 2 grid Now, Diagonal 1 Product = a × (a + 8) = a2 + 8a Diagonal 2 Product = (a + 7) × (a + 1) = a(a + 1) + 7(a + 1) = a2 + a + 7a + 7 = a2 + 8a + 7 Thus, product of the second diagonal is always 7 more than the product of the first diagonal. Example from image: 4 × 12 = 48, and 5 × 11 = 55 Difference is 55 - 48 = 7)

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CA Maninder Singh is a Chartered Accountant for the past 16 years. He also provides Accounts Tax GST Training in Delhi, Kerala and online.