You are here
Question 14 - Figure it out - Page 132, 133, 134 - Chapter 5 Class 8 - Number Play (Ganita Prakash)
Last updated at August 14, 2026 by Teachoo
Figure it out - Page 132, 133, 134
Ganita Prakash Class 8 - Part 1, 2
Chapter 5 Class 8 - Number Play (Ganita Prakash)
- Sum of Consecutive Numbers
- Parity of Arithmetic & Algebraic Expressions
- Pairs to Make Fours
- Factors and Multiples
- Always, Sometimes, or Never
- What Remains?
- Figure it out - Page 122, 123
- Divisibility Rules - 2, 5, 10 and 3
- Shortcut for Divisibility by 9
- Figure it out - Page 126
- Shortcut for Divisibility by 11
- Divisibility Shortcuts for Other Numbers
- Digital Roots
- Figure it out - Page 131
- Digits in Disguise
-
Figure it out - Page 132, 133, 134
Transcript
Question 14 Is the product of two consecutive integers always multiple of 2? Why? What about the product of these consecutive integers? Is it always a multiple of 6? Why or why not? What can you say about the product of 4 consecutive integers? What about the product of five consecutive integers?2 consecutive integers: One is always even. Product is divisible by 2? Yes, Always. Example: 4, 5 Product = 4 × 5 = 20 is divisible by 2 3 consecutive integers: At least one is even and one is a multiple of 3 . Product is divisible by 2 × 3 = 6? Yes, Always. Example: 4, 5, 6 Product = 4 × 5 × 6 = 120 is divisible by 6 4 consecutive integers: Product is divisible by 4 × 3 × 2 × 1 = 24 Example: 4, 5, 6, 7 Product = 4 × 5 × 6 × 7 = 840 is divisible by 24 5 consecutive integers: Product is divisible by 5 × 4 × 3 × 2 × 1 = 120 Example: 4, 5, 6, 7, 8 Product = 4 × 5 × 6 × 7 = 6720 is divisible by 120
