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Question 3 - Figure it out - Page 132, 133, 134 - Chapter 5 Class 8 - Number Play (Ganita Prakash)
Last updated at July 23, 2026 by Teachoo
Figure it out - Page 132, 133, 134
Class 8 (Ganita Prakash - 1, 2 & Old NCERT)
Chapter 5 Class 8 - Number Play (Ganita Prakash)
- Sum of Consecutive Numbers
- Parity of Arithmetic & Algebraic Expressions
- Pairs to Make Fours
- Factors and Multiples
- Always, Sometimes, or Never
- What Remains?
- Figure it out - Page 122, 123
- Divisibility Rules - 2, 5, 10 and 3
- Shortcut for Divisibility by 9
- Figure it out - Page 126
- Shortcut for Divisibility by 11
- Divisibility Shortcuts for Other Numbers
- Digital Roots
- Figure it out - Page 131
- Digits in Disguise
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Figure it out - Page 132, 133, 134
Transcript
Question 3 When is the sum of two multiples of 3, a multiple of 6 and when is it not? Explain the different possible cases, and generalise the pattern.Now, A multiple of 6 must be divisible by 2 and 3 . Since we are adding multiples of 3 , the sum is already divisible by 3. We just need to check if the sum is even (divisible by 2). Let’s check different cases If you add two odd multiples of 3 (e.g., 3+9=12 ), the sum is even (Multiple of 6 ). If you add two even multiples of 3 (e.g., 6+12=18 ), the sum is even (Multiple of 6 ). If you add one odd and one even (e.g., 3+6=9), the sum is odd (Not a multiple of 6). So, the answer is The sum is a multiple of 6 when both numbers are odd or both numbers are even.
