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Question 13 - Figure it out - Page 132, 133, 134 - Chapter 5 Class 8 - Number Play (Ganita Prakash)
Last updated at January 8, 2026 by Teachoo
Figure it out - Page 132, 133, 134
Class 8 (Ganita Prakash - 1, 2 & Old NCERT)
Chapter 5 Class 8 - Number Play (Ganita Prakash)
- Sum of Consecutive Numbers
- Parity of Arithmetic & Algebraic Expressions
- Pairs to Make Fours
- Factors and Multiples
- Always, Sometimes, or Never
- What Remains?
- Figure it out - Page 122, 123
- Divisibility Rules - 2, 5, 10 and 3
- Shortcut for Divisibility by 9
- Figure it out - Page 126
- Shortcut for Divisibility by 11
- Divisibility Shortcuts for Other Numbers
- Digital Roots
- Figure it out - Page 131
- Digits in Disguise
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Figure it out - Page 132, 133, 134
Transcript
Question 13 Choose any 3 numbers. When is their sum divisible by 3? Explore all possible cases and generalise.General Rule: The sum is divisible by 3 if: All three numbers have a remainder of 0 when divided by 3 (e.g., 3, 6, 9). All three numbers have a remainder of 1 (e.g., 1, 4, 7). All three numbers have a remainder of 2 (e.g., 2, 5, 8). One has remainder 0 , one has remainder 1 , and one has remainder 2 (eg: 6, 4, 5)
