If 48a23b is a multiple of 18, list all possible pairs of values for a - Figure it out - Page 132, 133, 134

part 2 - Question 5 - Figure it out - Page 132, 133, 134 - Chapter 5 Class 8 - Number Play (Ganita Prakash) - Class 8 (Ganita Prakash - 1, 2 & Old NCERT)
part 3 - Question 5 - Figure it out - Page 132, 133, 134 - Chapter 5 Class 8 - Number Play (Ganita Prakash) - Class 8 (Ganita Prakash - 1, 2 & Old NCERT)

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Question 5 If 48a23b is a multiple of 18, list all possible pairs of values for a and b.If a number is divisible by 18, it means It is divisible by 2 (must be even) It is divisible by 9 (sum of digits is divisible by 9). Note: We choose 2 & 9 because they have no common factors Divisibility by 2 Number is 48a23b Since the number has to be even. b can be 0, 2, 4, 6, 8 Divisibility by 9 Number is 48a23b Sum of digits = 4 + 8 + a + 2 + 3 + b = 17 + a + b The next multiples of 9 after 17 are 18, 27, 36 Finding pairs If Sum = 18 17+๐‘Ž+๐‘=18 ๐‘Ž+๐‘=18โˆ’17 ๐’‚+๐’ƒ=๐Ÿ Since ๐’ƒ is even, pair coud be ๐‘=0,๐‘Ž=1. โˆด Pair: (๐’‚=๐Ÿ,๐’ƒ=๐ŸŽ) If Sum =๐Ÿ๐Ÿ•: 17+๐‘Ž+๐‘=27 ๐‘Ž+๐‘=27โˆ’17 ๐’‚+๐’ƒ=๐Ÿ๐ŸŽ We can have multiple cases here, like If ๐‘=2,๐‘Ž=8 If ๐‘=4,๐‘Ž=6 If ๐‘=6,๐‘Ž=4 If ๐‘=8,๐‘Ž=2 ( ๐‘=0 implies ๐‘Ž=10, not a digit). Thus, the Possible pairs (๐‘Ž,๐‘) are (๐Ÿ,๐ŸŽ),(๐Ÿ–,๐Ÿ),(๐Ÿ”,๐Ÿ’),(๐Ÿ’,๐Ÿ”),(๐Ÿ,๐Ÿ–)

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CA Maninder Singh is a Chartered Accountant for the past 16 years. He also provides Accounts Tax GST Training in Delhi, Kerala and online.