Exterior Angles
Last updated at November 7, 2025 by Teachoo
Transcript
Exterior AnglesFor any triangle Interior Angles = ∠ 1, ∠ 2, ∠ 3 Exterior Angles = ∠ 4, ∠ 5, ∠ 6 Let’s do a question Find ∠ ACD, if ∠ A = 50°, and ∠ B = 60°. From angle sum property of triangle ∠ A + ∠ B + ∠ ACB = 180° 50° + 60° + ∠ ACB = 180° 110° + ∠ ACB = 180° ∠ ACB = 180° – 110° Exterior angle ∠ ACB = 70° Since BCD is a line Applying linear pair ∠ ACB + ∠ ACD = 180° 70° + ∠ ACD = 180° ∠ ACD = 180° – 70° ∠ ACD = 110° We can also write ∠ ACD = ∠ A + ∠ B Which leads us to the property Exterior Angle is sum of interior opposite angles Exterior angle