[Ganita Prakash] Construct Triangle with sides 3.5 cm, 3.5 cm, 3.5 cm - Constructing a Triangle when its Sides are given

part 2 - Question (e) - Page 150 - Constructing a Triangle when its Sides are given - Chapter 7 Class 7 - A tale of three Intersecting Lines (Ganit Prakash) - Class 7 (Ganita Prakash 1, 2 & old NCERT)
part 3 - Question (e) - Page 150 - Constructing a Triangle when its Sides are given - Chapter 7 Class 7 - A tale of three Intersecting Lines (Ganit Prakash) - Class 7 (Ganita Prakash 1, 2 & old NCERT)
part 4 - Question (e) - Page 150 - Constructing a Triangle when its Sides are given - Chapter 7 Class 7 - A tale of three Intersecting Lines (Ganit Prakash) - Class 7 (Ganita Prakash 1, 2 & old NCERT)
part 5 - Question (e) - Page 150 - Constructing a Triangle when its Sides are given - Chapter 7 Class 7 - A tale of three Intersecting Lines (Ganit Prakash) - Class 7 (Ganita Prakash 1, 2 & old NCERT) part 6 - Question (e) - Page 150 - Constructing a Triangle when its Sides are given - Chapter 7 Class 7 - A tale of three Intersecting Lines (Ganit Prakash) - Class 7 (Ganita Prakash 1, 2 & old NCERT)

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Transcript

Question (e) - Page 150 Construct triangles having the following sidelengths (all the units are in cm): (e) 3.5, 3.5, 3.5 First we draw a rough sketch This is an equilateral triangle Let’s try to draw it now Steps of construction 1. Draw a line segment AB of length 3.5 cm 2. Taking 3.5 cm as radius, and A as center, we draw a full circle lightly 3. Taking 3.5 cm as radius, and B as center, we draw a full circle lightly Now, where these two circles intersect is our point C 5. Join AC and BC and label the sides Thus, Δ ABC is the required triangle

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 15 years. He provides courses for Maths, Science and Computer Science at Teachoo