Construct an Equilateral Triangle of side 4.5 cm - Teachoo - Constructing Equilateral Triangle

part 2 - Construct an Equilateral Triangle of side 4.5 cm - Constructing Equilateral Triangle - Chapter 7 Class 7 - A tale of three Intersecting Lines (Ganit Prakash) - Class 7 (Ganita Prakash 1, 2 & old NCERT)
part 3 - Construct an Equilateral Triangle of side 4.5 cm - Constructing Equilateral Triangle - Chapter 7 Class 7 - A tale of three Intersecting Lines (Ganit Prakash) - Class 7 (Ganita Prakash 1, 2 & old NCERT)
part 4 - Construct an Equilateral Triangle of side 4.5 cm - Constructing Equilateral Triangle - Chapter 7 Class 7 - A tale of three Intersecting Lines (Ganit Prakash) - Class 7 (Ganita Prakash 1, 2 & old NCERT)
part 5 - Construct an Equilateral Triangle of side 4.5 cm - Constructing Equilateral Triangle - Chapter 7 Class 7 - A tale of three Intersecting Lines (Ganit Prakash) - Class 7 (Ganita Prakash 1, 2 & old NCERT)

Remove Ads Share on WhatsApp

Transcript

Construct an Equilateral Triangle of side 4.5 cm Let’s first we draw a rough sketch In an equilateral triangle, all sides are equal So, our triangle looks like Now, let’s draw it Steps of construction 1. Draw a line segment AB of length 4.5 cm 2. Taking 4.5 cm as radius, and A as center, draw an arc – not full circle just an arc 3. Taking 4.5 cm as radius, and B as center, draw another arc. Let C be the point where the two arcs intersect Join AC and BC and label the sides Thus, Δ ABC is the required triangle

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 15 years. He provides courses for Maths, Science and Computer Science at Teachoo