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Constructing Rectangle in which Diagonal divides the opposite angles
Last updated at July 16, 2026 by Teachoo
Constructing Rectangles & Squares with Diagonals
Class 6 (Ganita Prakash & Old NCERT)
Chapter 8 Class 6 - Playing with Constructions (Ganita Prakash)
- Introduction
- Constructing Circle, Person, Waves, Eyes
- Figure it out - Page 191
- Constructing Squares & Rectangles
- Figure it out - Page 194
- Constructing Squares & Rectangles
- An Exploration in Rectangles
- Construct Breaking Rectangles
- Questions - Page 201 to 203
- Diagonals of Rectangles and Squares
-
Constructing Rectangles & Squares with Diagonals
- Construction Questions - Page 211
- Constructing a House (with Questions)
Transcript
Constructing Rectangle in which Diagonal divides the opposite anglesConstruct a rectangle in which one of the diagonals divides the opposite angles into 60° and 30°. Let’s make a figure For rectangle ABCD Rectangle ABCD where Diagonal AC divides it into 60° and 30° We have to assume a length of Rectangle Let Length of Rectangle = AB = 7 cm Steps of construction 1. Draw side AB of length 7 cm 2. Now, we draw 90° from point A 3. Now, we draw 90° from point B From point A - we draw 30° Where that line intersects the perpendicular from point B is point C To mark point D – we can use two Methods Method 1 to mark point D 6. We draw 90° from point C. 7. Where that line intersects perpendicular from A is point D Method 2 to mark point D 6. We measure BC using compass and then mark point D on line perpendicular to A such that AD = BC 7. Join CD Thus, ABCD is our required rectangle
