Construct a Rectangle Whose Diagonal Divides opposite angles 50° & 40° - Construction Questions - Page 211

part 2 - Question 1 - Construction Questions - Page 211 - Chapter 8 Class 6 - Playing with Constructions (Ganita Prakash) - Class 6 (Ganita Prakash & Old NCERT)
part 3 - Question 1 - Construction Questions - Page 211 - Chapter 8 Class 6 - Playing with Constructions (Ganita Prakash) - Class 6 (Ganita Prakash & Old NCERT) part 4 - Question 1 - Construction Questions - Page 211 - Chapter 8 Class 6 - Playing with Constructions (Ganita Prakash) - Class 6 (Ganita Prakash & Old NCERT) part 5 - Question 1 - Construction Questions - Page 211 - Chapter 8 Class 6 - Playing with Constructions (Ganita Prakash) - Class 6 (Ganita Prakash & Old NCERT) part 6 - Question 1 - Construction Questions - Page 211 - Chapter 8 Class 6 - Playing with Constructions (Ganita Prakash) - Class 6 (Ganita Prakash & Old NCERT) part 7 - Question 1 - Construction Questions - Page 211 - Chapter 8 Class 6 - Playing with Constructions (Ganita Prakash) - Class 6 (Ganita Prakash & Old NCERT)

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Transcript

Question 1 Construct a rectangle in which one of the diagonals divides the opposite angles into 50° and 40°.Let’s make a figure For rectangle ABCD Rectangle ABCD where Diagonal AC divides it into 50° and 40° We have to assume a length of Rectangle Let Length of Rectangle = AB = 7 cm Steps of construction 1. Draw side AB of length 7 cm 2. Now, we draw 90° from point A 3. Now, we draw 90° from point B From point A - we draw 40° Where that line intersects the perpendicular from point B is point C 6. We draw 90° from point C. 7. Where that line intersects perpendicular from A is point D Thus, ABCD is our required rectangle

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