Ex 9.2, 17 - P (a, b) is mid-point of a line segment axes - Ex 9.2

part 2 - Ex 9.2, 17 - Ex 9.2 - Serial order wise - Chapter 9 Class 11 Straight Lines
part 3 - Ex 9.2, 17 - Ex 9.2 - Serial order wise - Chapter 9 Class 11 Straight Lines part 4 - Ex 9.2, 17 - Ex 9.2 - Serial order wise - Chapter 9 Class 11 Straight Lines part 5 - Ex 9.2, 17 - Ex 9.2 - Serial order wise - Chapter 9 Class 11 Straight Lines

 

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Ex 9.2, 17 P (a, b) is the mid-point of a line segment between axes. Show that equation of the line is š‘„/š‘Ž + š‘¦/š‘ = 2 Plotting x-axis and y-axis Let l be a line intersecting x-axis at A and y-axis at B Let P(a, b) be midpoint of AB Here Let co-ordinates of A be (p, 0) Let co-ordinates of B be (0, q) We know that mid point of a line joining points (x1, y1) & (x2, y2) is ((š‘„_1 āˆ’ š‘„_2 )/2, (š‘¦_1 āˆ’ š‘¦_2)/2) Mid point of a line joining points A (p,0) & B(0, q) is P(a,b) Putting values (a, b) = ((š‘ + 0)/2, (0 + š‘ž)/2) (a, b) = (š‘/2, š‘ž/2) So, p = 2a, q = 2b So, points A = (p, 0) = (2a, 0) B = (0, q) = (0, 2b) Finding equation of line by two point equation of line (y – y1) = (š‘¦_2 āˆ’ š‘¦_1)/(š‘„_2 āˆ’ š‘„_1 ) (x – x1) For equation of line l passing through (2a, 0) & (0, 2b) Here x1 = 2a, y1 = 0 x2 = 0, y2 = 2b Putting values (y – y1) = (š‘¦_2 āˆ’ š‘¦_1)/(š‘„_2 āˆ’ š‘„_1 ) (x – x1) (y – 0) = (2š‘ āˆ’ 0)/(0 āˆ’ 2š‘Ž) ( x – 2a) y = 2š‘/(āˆ’2š‘Ž) (x – 2a) y = (āˆ’b)/a (x – 2a) ay = –bx + 2ab ay + bx = 2ab Dividing by ab š‘Žš‘¦/š‘Žš‘ + š‘š‘„/š‘Žš‘ = 2š‘Žš‘/š‘Žš‘ š‘¦/š‘ + š‘„/š‘Ž = 2 š‘„/š‘Ž + š‘¦/š‘ = 2 Hence, the equation of line is š‘„/š‘Ž + š‘¦/š‘ = 2 Hence proved

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