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Last updated at Feb. 3, 2020 by Teachoo

Transcript

Ex 10.2, 8 Find the equation of the line which is at a perpendicular distance of 5 units from the origin and the angle made by the perpendicular with the positive x-axis is 30° We need to calculate equation of line Perpendicular distance of line from origin is 5 units & Normal makes an angle of 30° with the positive x-axis By the normal from Equation of line is x cos ω + y sin ω = p. where, p = normal distance from the origin & ω = angle which makes by the normal with positive x-axis Here p = 5 & ω = 30° Putting values x cos ω + y sin ω = p x cos 30° + y sin 30° = 5 x √3/2 + y 1/2 = 5 (√3 𝑥 + 𝑦)/2 = 5 √𝟑 𝒙 + y = 10 Thus, equation of line is √3 𝑥 + y = 10

Chapter 10 Class 11 Straight Lines

Concept wise

- Cordinate geometry questions
- Slope - Finding slope
- Slope - Prependicularity
- Angle between two lines by Slope
- Collinearity of 3 points by sliope
- Point Slope form
- Slope-Intercept form
- Intercept form
- Normal form
- Given Statement
- Two lines // or/and prependicular
- Angle between two lines
- Distance - Between two parallel lines
- Distance of a point from a line
- Distance of a point from a line along a line
- Other Type of questions - Area of Triangle formed
- Other Type of questions - 3 lines Concurrent
- Other Type of questions - Image
- Other Type of questions - Mix

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.