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Ex 9.2, 11 - Chapter 9 Class 11 Straight Lines
Last updated at August 8, 2026 by Teachoo
Chapter 9 Class 11 Straight Lines
Concept wise
- Cordinate geometry questions
- Slope - Finding slope
- Slope - Prependicularity
- Angle between two lines by Slope
- Collinearity of 3 points by sliope
- Point Slope form
- Slope-Intercept form
-
Intercept form
- Normal form
- Given Statement
- Two lines // or/and prependicular
- Angle between two lines
- Distance - Between two parallel lines
- Distance of a point from a line
- Distance of a point from a line along a line
- Other Type of questions - Area of Triangle formed
- Other Type of questions - 3 lines Concurrent
- Other Type of questions - Image
- Other Type of questions - Mix
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Transcript
Ex 9.2, 12 Find the equation of a line that cuts off equal intercepts on the coordinate axes and passes through the point (2, 3). Equation of a line by intercept form is x/a + y/b = 1 Where a = x-intercept & b = y-intercept But given that x & y intercept are equal a = b Thus, equation of line is x/a + y/a = 1 x + y = a x + y a = 0 Now we need to find value of a Since the line passes through the point (2, 3) Point (2, 3) will satisfying the equation of line Putting x = 2 & y = 3 in (1) 2 + 3 a = 0 5 a = 0 a = 5 Now, Equation of line becomes x + y a = 0 x + y 5 = 0 Hence the required equation of line is x + y 5 = 0
