There are two dice whose faces have these numbers: –1, 2, –3, 4, –5, 6 - Figure it out - Page 265, 266

part 2 - Question 3 - Figure it out - Page 265, 266 - Chapter 10 Class 6 - The other side of Zero (Ganita Prakash) - Class 6 (Ganita Prakash & Old NCERT)
part 3 - Question 3 - Figure it out - Page 265, 266 - Chapter 10 Class 6 - The other side of Zero (Ganita Prakash) - Class 6 (Ganita Prakash & Old NCERT)

Remove Ads Share on WhatsApp

Transcript

Question 3 There are two dice whose faces have these numbers: –1, 2, –3, 4, –5, 6. The smallest possible sum upon rolling these dice is –10 = (–5) + (–5) and the largest possible sum is 12 = (6)+(6). Some numbers between (–10) and (+12) are not possible to get by adding numbers on these two dice. Find those numbers.Since have two dices, we can make a table like Filling in the table Detailed Calculation of Each Sum Here is the step-by-step addition for all 36 possible outcomes. -2 -4 -6 -4 -6 -8 -6 -8 -10 Possible Sums These are all the unique sums that can be achieved by adding the faces of the two dice. There are 18 unique outcomes. -10 -8 -6 -4 -3 -2 -1 1 3 4 5 6 8 10 12 Impossible Sums Within the total range of -10 to 12 , these are the numbers that can never be rolled.

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 15 years. He provides courses for Maths, Science and Computer Science at Teachoo