This problem was posed by Chaturveda Pṛithūdakasvāmī (c. 860 CE) - Some Problems Involving Fractions (Page 190, 191)

part 2 - Example 5 - Some Problems Involving Fractions (Page 190, 191) - Chapter 8 Class 7 - Working with Fractions (Ganita Prakash) - Class 7 (Ganita Prakash 1, 2 & old NCERT)
part 3 - Example 5 - Some Problems Involving Fractions (Page 190, 191) - Chapter 8 Class 7 - Working with Fractions (Ganita Prakash) - Class 7 (Ganita Prakash 1, 2 & old NCERT)

Remove Ads Share on WhatsApp

Transcript

Example 5 This problem was posed by Chaturveda Pṛithūdakasvāmī (c. 860 CE) in his commentary on Brahmagupta’s book Brāhmasphuṭasiddhānta. Four fountains fill a cistern. The first fountain can fill the cistern in a day. The second can fill it in half a day. The third can fill it in a quarter of a day. The fourth can fill the cistern in one fifth of a day. If they all flow together, in how much time will they fill the cistern? Let us solve this problem step by step. In a day, the number of times — • the first fountain will fill the cistern is 1 ÷ 1 = 1 • the second fountain will fill the cistern is 1 ÷ 1/2 = _____ • the third fountain will fill the cistern is 1 ÷ 1/4 = _____ • the fourth fountain will fill the cistern is 1 ÷ 1/5 = _____ The number of times the four fountains together will fill the cistern in a day is ___ + ____ + ___ + ____ = 12. In a day, the number of times, First fountain will fill the cistern is = 1 ÷ 1 = 1 times Second fountain will fill the cistern is = 1 ÷ 1/2 = 1 ×2/1 = 2 times Third fountain will fill the cistern is = 1 ÷ 1/4 = 1 ×4/1 = 4 times Fourth fountain will fill the cistern is = 1 ÷ 1/5 = 1 ×5/1 = 5 times Thus, The number of times the four fountains together will fill the cistern in a day is 1 + 2 + 4 + 5 = 12.

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 15 years. He provides courses for Maths, Science and Computer Science at Teachoo