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Question 2 (b) - Figure it out - Page 110, 111 - Chapter 5 Class 6 - Prime Time (Ganita Prakash)
Last updated at August 14, 2026 by Teachoo
Class 6 (Ganita Prakash & Old NCERT)
Chapter 5 Class 6 - Prime Time (Ganita Prakash)
- Factors and Multiples
- Common Multiples
- Common Factors
- Idli Vada Game
- Jumpy Jackpot
-
Figure it out - Page 110, 111
- Prime Numbers
- Figure it out - Page 114, 115
- Co-prime numbers (and art)
- Prime Factorisation
- Uses of Prime Factorisation
- Divisibility Tests
- Figure it out - Page 125, 126
- Fun with numbers
- Teachoo Questions - MCQs
- Teachoo Questions - Mix
- Teachoo Questions - Assertion Reasoning
- Teachoo Questions - Case Based
Transcript
Question 2 (b) Who am I? b. I am a number less than 100. Two of my factors are 3 and 5. One of my digits is 1 more than the other.Numbers having factor 3 & 5 would be multiples of 3 & 5 i..e Number would be multiple of 3 × 5 = 15 Finding multiples of 15 which are less than 100 15 × 1 = 15 15 × 2 = 30 15 × 3 = 45 15 × 4 = 60 15 × 5 = 75 15 × 6 = 90 15 × 7 = 105 So, possible numbers could be 15, 30, 45, 60, 75 or 90 Now, given that One of my digits is 1 more than the other Only number 45 fits the bill ∴ Our answer is 55
