Last updated at May 29, 2018 by Teachoo

Transcript

Misc 5 (Method 1) How many 6-digit numbers can be formed from the digits 0, 1, 3, 5, 7 and 9 which are divisible by 10 and no digit is repeated? A number is divisible by 10 if 0 occur at the units place We need to formed 6 digit number whose unit place is fix Now we need to fill up 5 place with the remaining digit 1, 3, 5, 7, & 9 Hence, n = Number of digits = 5 & r = Number of places to fill = 5 Number of 6 digit numbers = 5P5 = 5!/(5 − 5)! = 5!/0! = 5!/1 = 5 × 4 × 3 × 2 × 1 = 120 Misc 5 (Method 2) How many 6-digit numbers can be formed from the digits 0, 1, 3, 5, 7 and 9 which are divisible by 10 and no digit is repeated? A number is divisible by 10 if 0 occur at the units place We need to formed 6 digit number whose unit place is fix Now we need to fill up 5 place with the remaining digit 1, 3, 5, 7, & 9 Number of 6 digit numbers = 1 × 5 × 4 × 3 × 2 × 1 = 120

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.