Ex 5.3, 8 - Chapter 5 Class 11 - Solve equation - Ex 5.3

  1. Chapter 5 Class 11 Complex Numbers
  2. Serial order wise
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Ex5.3, 8 Solve the equation √3x2 − √2x + 3 √3 = 0 √3x2 − √2x + 3 √3 = 0 The above equation is of the form 𝑎𝑥2 + 𝑏𝑥 + 𝑐 = 0 Where a = √3 , b = − √2, and c = 3√3 x = (−𝑏 ± √( 𝑏^2 − 4𝑎𝑐 ))/2𝑎 = (−("− " √2 ) ± √(("− " √2 )^2− 4 × √(3 )× 3√3) )/(2 × √3) = (√2 ± √(2 − 4 × 3 × 3))/(2√3) = (√2 ± √(2 − 36))/(2√3) = (√2 ± √(− 34))/(2√3) = (√2 ± √(−1 × 34))/(2√3) = (√2 ± √(−1 )× √(34 ))/(2√3) = (√2 ± √34 𝑖)/(2√3) Thus, 𝑥 = (√2 ± √34 𝑖)/(2√3)

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